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3 years ago

13

The number of hours you study for an exam impacts your grade. What is a reasonable value of the range

2 answers:

Akimi4 [234]3 years ago

8 0

Answer: 80

Step-by-step explanation:

Monica [59]3 years ago

3 0

Answer:

b.2/3

Step-by-step explanation:

I think this would be the most reasonable.

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What is the length of line segment KJ?<br><br> 2√3 units<br> 3√2units<br> 3√3units<br> 3√5units

Pavlova-9 [17]

KJ^2=6^2+3^2
KJ=the square root of 36+9
KJ=square root of 45
kJ= 3 times the square root of 5
The answer is D

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3 years ago

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In which geometry is there no line parallel to a given line through a point not on the line?

tangare [24]

Answer:

Given a line and a point not on it, no lines parallel to the given line can be drawn through the point. you get an elliptic geometry.

Step-by-step explanation:

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3 years ago

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Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

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4 years ago

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Could someone help with my previously asked questions

m_a_m_a [10]

Answer:

ill try! <3

Step-by-step explanation:

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3 years ago

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Zachary purchased a computer for 1800 on a payment plan. three months after he purchased the computer, his balance was 1350. fiv

nadezda [96]

(750m) - 1050 = b

1800 - 1050 = 750 dollars lost.

So (750m) - 1050 = b will give you the balance.

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4 years ago