Answer:
![\boxed{x](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3C1%5Cto%20x%5Cin%28-%5Cinfty%2C%5C%201%29%7D)
Step-by-step explanation:
![-6x+5>-1\qquad\text{subtract 5 from both sides}\\\\-6x>-6\qquad\text{change the signs}\\\\6x](https://tex.z-dn.net/?f=-6x%2B5%3E-1%5Cqquad%5Ctext%7Bsubtract%205%20from%20both%20sides%7D%5C%5C%5C%5C-6x%3E-6%5Cqquad%5Ctext%7Bchange%20the%20signs%7D%5C%5C%5C%5C6x%3C6%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%206%7D%5C%5C%5C%5Cx%3C1)
A^2 + b^2 = c^2
9^2 + 12^2= c^2
81 + 144 = 225
C= 15
The answer is 15 yards.
Since there are 5 volumes to rearrange and the way to find the number of combinations to rearrange objects is by multiplying numbers that you count down from the original number (5 in this case) to 1, the problem is set up as 5×4×3×2×1.
Now solve!
5×4×3×2×1
20×3×2×1
60×2×1
120×1
120
120 ways to rearrange the volumes.
Answer:
196pi * 80/360 or ~136.8
Step-by-step explanation:
196pi * 80/360
or ~136.8
The point of intersection for the two equations is: (4, 360).
<h3>What is the Point of Intersection of Two Equations?</h3>
The point of intersection is the point where the two equations becomes equal to each other.
To find the point of intersection for, y = 100 + 65x and y = 40 + 80x, set both equations equal to each other and solve for both x and y.
Thus:
100 + 65x = 40 + 80x
100 - 40 = 80x - 65x
60 = 15x
4 = x
Substitute x = 4 into the first equation
y = 100 + 65(4)
y = 360
Therefore, the point of intersection for the two equations is: (4, 360).
Learn more about point of intersection on:
brainly.com/question/11190011