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Ede4ka [16]
3 years ago
8

The product of a number and -3 is less than 27

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

-8

Step-by-step explanation:

-8×-3 =24 thats yeaaaa

You might be interested in
3 + 1/3 equals b - 23 State the problem
Viefleur [7K]

Answer:

b=\frac{79}{3} or b=26.33

Step-by-step explanation:

Assuming the question to be finding the value of b.

3+\frac{1}{3}=b-23

Solution:

Rewrite the equation as.

b-23=3+\frac{1}{3}

first we solve right side of the equation.

b-23=\frac{3\times 3+ 1}{3}

b-23=\frac{9+ 1}{3}

b-23=\frac{10}{3}

Add 23 both side of the equation.

b-23+23=\frac{10}{3}+23

b=\frac{10+23\times 3}{3}

b=\frac{10+69}{3}

b=\frac{79}{3}

or

b=26.33

Therefore, the value of b=\frac{79}{3} or b=26.33

5 0
3 years ago
Combine like terms<br><br><br> -2/3p + 1/5 - 1 + 5/6p
Bezzdna [24]
1/6p - 4/5

Explanation: -2/3p needs to have the same denominator as 5/6p so they can combine. (Note, whatever sign is in front of a number determines if it is negative or positive. Your equation indicates that the bolded parts are negative and the other parts are positive: -2/3p + 1/5 - 1 + 5/6p. So what we are really doing in an equation like this is combining some numbers together)
-2/3p and 5/6p and the least common multiple of six, so we adjust the numbers to each have a denominator of 6. 5/6p is already there, so we need to adjust -2/3p.
We can multiply both the numerator and denominator by 2 to turn -2/3p into -4/6p. -4/6p has the same value as -2/3p, and now it also has the same denominator as 5/6p!
We then have to combine like terms, therefore combining -4/6p with 5/6p. When adding together fractions, the denominator does not change (this is why both numbers must have the same denominators). So our answer will be _/6p. So we combine -4 with 5, giving us one.
Therefore, -2/3p combined with 5/6p is 1/6p.
Now we have to combine our other set of like terms, 1/5 and -1. We can do this the same way that we combined the other numbers.
1/5 and -1 need the same denominator. This is simple because 1 can easily be figured out with any denominator, as long as the numerator and denominator are the same. This would make 1 = 5/5. But we need it negative, so it would be -5/5.
Now that we have common denominators, we can combine!
1/5 - 5/5
Remember what we said before, the solution will have the same denominator, so all we need to do is (in this case) subtract the numerators.
1 - 5 = 4
So that would be -4/5.
With the like terms combined, we just need to put our two combinations (1/6p and -4/5) together!

Our answer: 1/6p - 4/5

I hope that helps!
5 0
3 years ago
How to do this question plz ​
hjlf

Answer:

\underline{ \boxed{ \underline{part \: a}}}. \\the \: required \: distance  \: a part \: be \to \:  \boxed{\underline {\overline{p }  =79.23 \: km} }  \\  \\ \underline{ \boxed{ \underline{part \: b}}}. \\ the \: bearing \: of \: \boxed{ B } \: \: from \:  \boxed{ \underline{A}} \: is \to \boxed{ \underline{324 }\degree }

Step-by-step explanation:

\underline{ \boxed{ \underline{part \: a}}}. \\  l et \: the \: required \: distance  \: apart \: be \to \:  \boxed{ \overline  {p}} \\ let \:  \boxed{ \angle \: P} \: be \: the \: angle \: of \: seperation \: between \: both \: ships  :given \: by \to \\  P = (244 - 180) - (196 - 180 )= (64 -16) =  \boxed{48 \degree} \\ if \: ship \: A \: and \: B \: left  \: the \: port\: at \: (10:30) \:  \\ then \: at \: (14 :00) \: their \: time \: interval \: would \: be \to \\ (14 : 00) - (10 : 30) = \boxed{ 3.5 \: hrs} \\ ship \:  \boxed{A }\: distance \: from \: the \: port =( v \times t) = (30 \times 3.5) =  \boxed{105 \: km} \\ ship \:  \boxed{B }\: distance \: from \: the \: port =( v \times t) = (24 \times 3.5) =  \boxed{84\: km} \\n ow........we \: cant \: do \: much \: if \: their \: are \: no \: angles \: to \: work \: with \to \\ applying \:t he \: cosine \: rule : we \: have \to \\  \cos(P)  =  \frac{ {a}^{2} +  {b}^{2}  -  \overline{{p}^{2} } }{2(ab)}  \\  {a}^{2} +  {b}^{2}  -  \overline{{p}^{2} } = 2(ab) \cos(P)  \\ \overline{{p}^{2} } = {a}^{2} +  {b}^{2}  - \{2(ab) \cos(P)  \} \\ \overline{{p}^{2} }  =  {84}^{2}  +  {105}^{2}  -  \{2(84)(105) \cos(48 \degree)  \} \\\overline{{p}^{2} }  =  18,081 - 11,803.463897 \\ \overline{{p}^{2} }  = 6,277.536103 \\ \overline{p }  =  \sqrt{6,277.536103} \\  \boxed{\underline {\overline{p }  =79.23 \: km} } \\  \\  \underline{ \boxed{ \underline{part \: b}}}. \\ to \: sove \: this : we \: first \: find \:  angle \: \angle \: B : by \: applying \to \\  \frac{ \sin(B) }{b}  = \frac{  \sin(P) }{p}  \\  p \ast \sin(B)  = b \ast \sin(P) \\ B =  \sin {}^{ - 1} ( \frac{ b \ast \sin(P)}{p} )  \\ B =  \sin {}^{ - 1} ( \frac{ 105 \times  \sin(48 \degree)}{79.230903712} )  \\  \\ B =  \sin {}^{ - 1} ( \frac{ 78.030206678}{79.230903712} )    \\ \\ B =  \sin {}^{ - 1} (0.9848455971) \\  \boxed{B =  80 \degree} \\ hence \ :  the \: bearing \: of \: \boxed{ B } \: \: from \:  \boxed{ \underline{A}} \: is \to \\ 360 -  \{180 - (80 + 48 + 16) \} \\ 360 -(180 - 144 )\\ 360 -36 =   \boxed{324 \degree }

♨Rage♨

7 0
3 years ago
Subtract: (7x2 + 2x – 3) – (4x2 – 3x + 1)
Cloud [144]

Answer:    3x2+5x−4

The 2 behind 3x is an exponent

7 0
3 years ago
Use the elimination method to solve the system of equations. Choose the correct ordered pair.
Mandarinka [93]

Answer:

based on yahoo, cause my iq is like 10...the answer is B

Step-by-step explanation:


6 0
3 years ago
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