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Naily [24]
3 years ago
15

How would this be solved

Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

5

Step-by-step explanation:

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62.5

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Find the least common multiple of each pair of polynomials.<br> 5 y² - 80 and y + 4
kobusy [5.1K]

The least common multiple of each pair of the polynomial (5y² - 80) and

(y + 4) is equal to 5(y-4)(y+4).

As given in the question,

Given pair of the polynomial is (5y² - 80) and (y + 4)

Simplify the given polynomial using (a² -b²) = (a-b)(a +b)

(5y² - 80) = 5(y² -16)

⇒(5y² - 80) = 5(y² - 4²)

⇒(5y² - 80) = 5(y -4)(y + 4)

And  (y + 4) = (1) (y+4)

Least common multiple = 5(y-4)(y+ 4)

Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).

Learn more about least common multiple here

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Answer:

(3,2)

Step-by-step explanation:

3,2 is the answer...hope you can understand

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