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DENIUS [597]
3 years ago
10

Please help!!! Will give brainly!! 50 points

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0

The answer to your question is,

B. -0.625

-Mabel <3

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What is the solution to the inequality x + 4 + 2x ≤ 20 + 5x – 32
Illusion [34]

Answer:

x+4+2x = 20+5x-32

Step-by-step explanation:

x+4+2x

= 3x + 4

20+5x-32

= 20-32+5x

= 5x-12

Finding the value of X

3x+4 = 5x-12

= 4+12 = 5x-3x

= 16 = 2x

= 16/2 = X

= 8 = X

By putting the value of X in the equation

(3×8)+4

= 24 +4

= 28

(5×8)-12

= 40-12

28

28 = 28

so the X+4+2x < 20+5x-32 is wrong

5 0
3 years ago
What is k if : k!+48=48((k+1)^m)
lys-0071 [83]

Answer:

The value of k is greater than or equal to 0, i.e. k≥7.

Step-by-step explanation:

The given equation is

k!+48=48((k+1)^m)

The value of k must be a positive integer because k! is defined for k≥0, where k∈Z.

Subtract 48 from both the sides.

k!=48((k+1)^m)-48

k!=48((k+1)^m-1)

k!=48(k+1-1)(\frac{(k+1)^m-1}{(k+1)-1})

Using [\frac{r^m-1}{r-1}=r^{m-1}+r^{m-2}+...+1], we get

k!=48k((k+1)^{m-1}+(k+1)^{m-2}+...+1)

Divide both sides by 48k.

\frac{k!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

\frac{k(k-1)!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

\frac{(k-1)!}{48}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

Note: The value of m can be 0 or 1.

The value of k is positive integer, so the right hand side of the above equation must be a positive integer.

Since RHS of the equation is positive integer, therefore (k-1)! is completely divisible by 48.

k-1\geq 6

Add 1 on both sides.

k\geq 6+1

k\geq 7

Therefore the value of k is greater than or equal to 0.

4 0
4 years ago
A snowplow has maximum speed of 30 miles per hour on a dry highway. Its maximum speed decreases by 1.8 miles per hour every inch
kupik [55]
The depth of the snow would need to be 16 inches in order for the plow to stop moving
4 0
3 years ago
-18-16-14- 12-10-8-6Identify the inequality graphed on the number line.A)X-9&lt;3B)x+9&lt;3x-9 &lt;-3D)x +9&lt;-3
Murljashka [212]

The inequality graph shown is a graph of x < -6

The correct option is option B because it is the only one whose solution give x<-6

x + 9 < 3

x < 3 - 9

x < -6

Therefore the answer is B

5 0
1 year ago
Write a problem that uses a fraction greater than one
Softa [21]
One option is
1 + 7/3
8 0
3 years ago
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