We have three pythagoras:
4² + y² = z²
16² + y² = x²
x² + z² = 20²
Now let's think:
4² + y² = z²
y² = z² - 4²
16² + y² = x²
16² + z² - 4² = x²
x² + z² = 20²
16² + z²- 4² + z² = 20²
2z² = 20² - 16² + 4²
2z² = (2.10)² - (2^4)² + (2²)²
2z² = 2².10² - 2^8 + 2^4
z² = 2.10² - 2^7 + 2^3
z² = 200 - 128 + 8
z² = 208 - 128
z² = 80
z = √80
80 | 2
40 | 2
20 | 2
10 | 2
5 | 5
1
80 = 5.2^4
So
√80 = 4√5
z = 4√5
There are 120 different possible groups.
(10 * 9 * 8)/(3 * 2 * 1) + 120
Answer:
b = 0
Step-by-step explanation:
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
y = - 2x + 17 is in this form with slope m = - 2
• Parallel lines have equal slopes, hence
slope of line through the 2 points is - 2
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (b, 7)
m = = , hence
= - 2 ( cross- multiply )
- 2(b - 2) = 4
- 2b + 4 = 4 ( subtract 4 from both sides )
- 2b = 0 ⇒ b = 0
Answer:
ok.
what benchmark 1 1/8 is closet to (ps benchmarks on the side) and do the same for 2 2/5 . and the benchmarks that you found subtract them.
lol sorry though I don't know sorry
Step-by-step explanation:
Part A
t = 1
order pair (1 , 1,200)
t = 2
order pair (2 , 2,400)
part B
p = 1,200t