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Furkat [3]
3 years ago
12

How do i find the measure of these? i’m lost in math

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer: Answers and work are all in the picture that I attached. Hope this helps

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Rewrite the function by completing the square <br> f(x)=x^2-14x+63
Veseljchak [2.6K]

Answer:

f(x) = (x - 7)² - 14

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Vertex Form: f(x) = a(bx - c)² + d
  • Completing the Square: (b/2)²

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 14x + 63

<u>Step 2: Rewrite</u>

  1. Separate:                              f(x) = (x² - 14x) + 63
  2. Complete the Square:         f(x) = (x² - 14x + 49) + 63 - 49
  3. Simplify:                                f(x) = (x - 7)² - 14
8 0
3 years ago
Read 2 more answers
What are the greatest common factors of 28,35 and 56.
Zinaida [17]

Answer:

  7

Step-by-step explanation:

  28                    35                56

1 and 28         1 and 35       1 and 56

2 and 14         7 and 5         2 and 28

4 and 7                                4 and 14

                                            7 and 8

5 0
2 years ago
Find the surface area of the cylinder.Round your answer to the nearest tenth.
Delvig [45]

Answer:

The answer is 3438.16 i think

Step-by-step explanation:

6 0
3 years ago
Add 25 min (minutes), 30 min, 18 min, and 35 min. Then convert the sum to hours and minutes.
s2008m [1.1K]
The answer is1 hour 48 minutes
6 0
3 years ago
Read 2 more answers
I need help with this
evablogger [386]

Answer:

A) (-8, -16)

B) (0, 48)

C) (-4, 0), (-12, 0)

Step-by-step explanation:

A) the vertex is the minimum y value.

extremes of a function we get by using the first derivation and solving it for y' = 0.

y = x² + 16x + 48

y' = 2x + 16 = 0

2x = -16

x = -8

so, the vertex is at x=-8.

the y value is (-8)² + 16(-8) + 48 = 64 - 128 + 48 = -16

B) is totally simple. it is f(0) or x=0. so, y is 48.

C) is the solution of the equation for y = 0.

the solution for such a quadratic equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case here

a=1

b=16

c=48

x = (-16 ± sqrt(16² - 4×48)) / 2 = (-16 ± sqrt(256-192)) / 2 =

= (-16 ± sqrt(64)) / 2 = (-16 ± 8) / 2 = (-8 ± 4)

x1 = -8 + 4 = -4

x2 = -8 - 4 = -12

so the x- intercepts are (-4, 0), (-12, 0)

6 0
3 years ago
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