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3 years ago

What is the answer to this math problem

Mathematics

2 answers:

Nana76 [90]3 years ago

6 0

$1\dfrac{7}{10}+3\dfrac{13}{20}$

Method 1.

Find LCM of denominators:

LCM(10, 20) = 20

$1\dfrac{7\cdot2}{10\cdot2}+3\dfrac{13}{20}=1\dfrac{14}{20}+3\dfrac{13}{20}=(1+3)+\left(\dfrac{14+13}{20}\right)=4\dfrac{27}{20}=4\dfrac{20+7}{20}=5\dfrac{7}{20}$

Method 2.

Convert mixed numbers to decimal:

$1\dfrac{7}{10}=1.7\\\\3\dfrac{13}{20}=3\dfrac{13\cdot5}{20\cdot5}=3\dfrac{65}{100}=3.65\\\\1\dfrac{7}{10}+3\dfrac{13}{20}=1.7+3.65=5.35$

Alenkasestr [34]3 years ago

4 0

Hope this helps you..!!!

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2 years ago

What percent of 863.6 is 380

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Hello there! To solve types of questions like these, we can write and solve a proportion. We are looking for the percentage of 380 out of 863.6. Let's set up the proportion like this: 380/863.6 = x/100. Cross multiply the values in order to get 38,000 = 863.6x. Now, divide each side by 863.6 to isolate the "x". 38,000/863.6 is 44.00185271 or 44 when rounded to the nearest whole number. 380 is appox. 44% of 863.6.

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2 years ago

The function f(x) = 2x2 + 3x + 5, when evaluated, gives a value of 19. What is the function’s input value?

goldenfox [79]

$f(x)=\quad 2{ x }^{ 2 }+3x+5$

Let's called the input 'z'

When we plug 'z' in the function we get ;

$f(z)=\quad 2{ z }^{ 2 }+3z+5$

And we know that, this is equal to 19, so ;

$2{ z }^{ 2 }+3z+5=\quad 19$

Let's rearrange the equation.

$2{ z }^{ 2 }+3z+5=\quad 19\\ \\ 2{ z }^{ 2 }+3z=\quad 19-5\\ \\ 2{ z }^{ 2 }+3z=\quad 14\\ \\ 2{ z }^{ 2 }+3z-14=\quad 0$

So we have a quadratic equation here.

We'll use this formula to solve it :

$\frac { -b\pm \sqrt { { b }^{ 2 }-4ac } }{ 2a }$

The formula is used in equation formed like this :

$a{ x }^{ 2 }+bx+c=0$

In our equation,

a=2 , b=3 and c=-14

Let's plug in the values in the formula to solve,

$a=2\quad b=3\quad c=-14\\ \\ \frac { -3\pm \sqrt { 9-(4\cdot 2\cdot -14) } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9-(-112) } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9+112 } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 121 } }{ 4 } \\ \\ \frac { -3\pm 11 }{ 4 }$

So,

$z=\quad \frac { -3+11 }{ 4 } \quad ,\quad \frac { -3-11 }{ 4 } \\ \\ z=\quad \frac { 8 }{ 4 } \quad ,\quad \frac { -14 }{ 4 } \\ \\ z=\quad 2,\quad -\frac { 7 }{ 2 }$

So the input can be both, 2 and $-\frac{7}{2}$

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3 years ago

Read 2 more answers