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Vitek1552 [10]
2 years ago
9

I'm thinking it's either a or d but I'm not sure.

Mathematics
1 answer:
yan [13]2 years ago
8 0

Answer:

i think its d

Step-by-step explanation:

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pishuonlain [190]
V = -5 because you subtract 4 from both sides then divide both sides by -7 and you get -5
4 0
3 years ago
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I want the answer and way to do this problem.
user100 [1]

∠ABC = ∠CDA (given)

∠BCA = ∠DAC (given)

CA = AC (common side)

ASA congruence criterion = when two angles of two triangles are equal and their included side is also equal, we can consider those triangles to be congruent to each other.

Since two angles in triangle △ABC and△CDA are equal and since their included side is also equal we can conclude that they are congruent.

Therefore, △ABC ≅ △CDA under the ASA congruence criterion.

8 0
3 years ago
Simplify the following expression into the form a+bi where a and b are rational numbers
hoa [83]

- 28 - 40i

note that i² = (√-1)² = - 1

expand product of factors using FOIL

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= - 28 - 40i


7 0
3 years ago
Dilate the trapezoid using center (-3,4) and scale factor 1/2.
pochemuha

The coordinates of the vertices of the image of the trapezoid are given as;

A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) , D'(x, y) = (- 7 / 2, 5 / 2).

<h3>How to find the image of a trapezoid by dilation?</h3>

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described :

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where O(x, y) - Center of dilation

k - Scale factor

And P(x, y) - Coordinates of the original point, P'(x, y) - Coordinates of the resulting point.

Since k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4),

Therefore, the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2)  (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B';

B'(x, y) = O(x, y) + k [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2)  (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C';

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2)  [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k  [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

To learn more on dilations:

brainly.com/question/13176891

#SPJ1

3 0
1 year ago
Point G (6,-3) is translated 5 units to the left and 6 units up to form the point g. What are the coordinates of g prime
tino4ka555 [31]

Answer:

(1,3)

Step-by-step explanation:

If a point is translated to the left it must be subtracted from the original coordinates because the left is getting closer to the negative side of the graph. If it is being translated up that number should be added, so (6-5,-3+6) which is (1,3).

6 0
3 years ago
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