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Anna [14]
2 years ago
15

This is methane, Methane is gas that is found in small quantities in Earth's atmosphere. Methane is the simplest hydrocarbon,

Chemistry
1 answer:
const2013 [10]2 years ago
5 0

Answer:

CH4

Explanation:

I looked it up and took the test

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Is salt a iconically bounded compound?
Ann [662]

Answer:

ionically bonded.

Explanation:

7 0
3 years ago
Read 2 more answers
What property did mosely use to organize the periodic table?​
zhenek [66]

Answer:

nitrogen i think but not sure

Explanation:

4 0
3 years ago
A barium hydroxide solution is prepared by dissolving 2.06 g of Ba(OH)2 in water to make 32.9 mL of solution. What is the concen
navik [9.2K]

Answer:  1.36 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

To calculate the moles, we use the equation:

moles of solute= \frac{\text {given mass}}{\text {molar mass}}=\frac{2.06g}{171g/mol}=0.0120moles

Molarity=\frac{0.0120\times 1000}{32.9}=0.364M

The balanced reaction between barium hydroxide and perchloric acid:

2HCIO_4+Ba(OH_)2\rightarrow BaCIO_4+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

n_1=1\\M_1=?\\V_1=8.50mL\\n_2=2\\M_2=0.364M\\V_2=15.9mL

Putting values in above equation, we get:

1\times M_1\times 8.50=2\times 0.364\times 15.9\\\\M_1=1.36M

Thus the concentration of the acid is 1.36 M

4 0
3 years ago
In a study of the conversion of methane to other fuels, a chemical engineer mixes gaseous methane and gaseous water in a 0.778 L
sergejj [24]

Answer:

the water concentration at equilibrium is

⇒ [ H2O(g) ] = 0.0510 mol/L

Explanation:

  • CH4(g) + H2O(g) ↔ CO(g) + 3H2(g)

∴ Kc = ( [ CO(g) ] * [ H2 ]³ ) / ( [ CH4(g) ] * [ H2O(g) ] ) = 0,30

  • equilibrium:

⇒ [ CO(g) ] = 0.206 mol / 0.778 L = 0.2648 mol/L

⇒ [ H2(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L

⇒ [ CH4(g) ] = 0.187 mol / 0.778 L = 0.2404 mol/L

replacing in Kc:

⇒ ((0.2648) * (0.2404)³) / ([ H2O(g) ] * 0.2404 ) = 0.30

⇒ 0.0721 [ H2O(g) ] = 3.679 E-3

⇒ [ H2O(g) ] = 0.0510 mol/L

7 0
3 years ago
What volume of air is needed to burn completely 100cm of propane?
Evgesh-ka [11]

Answer:

See below

Explanation:

propane mole weight = 44 gm / mole

100 gm / 44 gm / mole = 2.27 moles

From the equation, 5 times as many moles of OXYGEN (O2)are required

   = 11.36 moles of oxygen

           at <u>STP</u> this is 254.55  liters of O2 (because 22.4 L = one mole) and

Using oxygen as 21 percent of air means that

      .21 x = 254.55 =       x = <u>1212.12 liters of air required </u>

5 0
2 years ago
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