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3 years ago

How many atoms does one formula unit of Sb4(SiO4)3 have

Chemistry

1 answer:

kotegsom [21]3 years ago

6 0

Answer:

There are 19 atom sin total in antimony silicate, $Sb_4(SiO_4)_3$ .

Explanation:

Number of antimony atoms = 4 × 1 = 4

Number of silicon atoms = 3 × 1 = 3

Number of oxygen atoms = 3 × 4 = 12

Number of atoms in antimony silicate:

= 4 + 3 + 12 = 19

There are 19 atom sin total in antimony silicate, $Sb_4(SiO_4)_3$ .

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How many moles of Manganese there in are 5.76 x 10(15) atoms of Mn?

aksik [14]

Answer:

1. 9.57 × 10^-9 moles.

2. 7.38mol

Explanation:

1.) To find the number of moles there are in the number of particles in an atom, we divide the number of particles (nA) by Avagadro's constant (6.02 × 10^23)

Hence, to find the number of moles (n) of Manganese (Mn), we say:

5.76 x 10^15 atoms ÷ 6.02 × 10^23

5.76/6.02 × 10^(15-23)

= 0.957 × 10^-8

= 9.57 × 10^-9 moles.

2.) Mole = mass/molar mass

Molar mass of sodium chloride (NaCl) = 23 + 35.5

= 58.5g/mol

mole = 431.6 g ÷ 58.5g/mol

mole = 7.38mol

7 0

3 years ago

Who know the song genius?

Angelina_Jolie [31]

Answer:

Explanation:

The one with sia??

3 0

2 years ago

What quantity of heat is required to raise the temperature of 460g of aluminum from 15C to 85C?

Hoochie [10]

Answer:

Q = 28.9 kJ

Explanation:

Given that,

Mass of Aluminium, m = 460 g

Initial temperature, $T_i=15^{\circ} C$

Final temperature, $T_f=85^{\circ}$

We know that the specific heat of Aluminium is 0.9 J/g°C. The heat required to raise the temperature is given by :

$Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=460\ g\times 0.9\ J/g^{\circ} C\times (85-15)^{\circ} C\\\\Q=28980\ J\\\\\text{or}\\\\Q=28.9\ kJ$

So, 28.9 kJ of heat is required to raise the temperature.

6 0

3 years ago

What is a Newton?<br> explain please

Lina20 [59]

Answer:

it is the unit of Force

Explanation:

force is equal to Newton

5 0

3 years ago

Read 2 more answers

Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re

laiz [17]

Answer:

80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.

Explanation:

From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.

6 0

3 years ago