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Liono4ka [1.6K]
3 years ago
11

What factors could have affected your results?

Chemistry
1 answer:
AleksandrR [38]3 years ago
8 0

Answer:

See below  

Step-by-step explanation:

heat gained by metal + heat lost by water = 0

           m₁C₁ΔT₁           +         m₂C₂ΔT₂         = 0

C₁ = -(m₂C₂ΔT₂)/(m₁ΔT₁)

The factors determining C₁ are

  • mass of water
  • temperature change of water (T_f - Ti)
  • mass of metal
  • temperature change of metal (T_f - Ti)

Any factor that makes the numerator higher or the denominator lower than what you thought, will give a calculated C₁ that is too high (and vice versa).

The major sources of uncertainty are probably in determining the temperatures, especially the initial and final temperatures of the metal. However, you will have to decide what the principal factors were in your experiment.

For example, did the metal have a chance to cool during the transfer to the calorimeter? How easy was it to determine the equilibrium temperature, etc?

Factors Affecting the Calculation of Specific Heat Capacity

<u>          Too Low                 </u>              <u>      Too high                   </u>              

Water                                             Water

    Mass less than thought                Mass more than thought

    Ti lower                                         Ti higher

    T_f higher                                       T_f lower

Metal                                              Metal

    Mass more than thought             Mass less than thought

    Ti higher                                       Ti lower

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Barium chloride solution was used to test for sulfate ions in the presence of dilute hydrochloric acid. What color precipitate w
Pani-rosa [81]

Answer:

white

Explanation:

A white precipitate of barium sulfate forms if sulfate ions are present. The hydrochloric acid is added first to remove any carbonate ions that might be present - they would also produce a white precipitate, giving a false positive result. Barium nitrate solution can be used instead of barium chloride solution

5 0
3 years ago
g Which ONE of the following pure substances will exhibit hydrogen bonding? A) methyl fluoride, FCH3 B) dimethyl ether, CH3C–O–C
luda_lava [24]

Answer:

C) formaldehyde, H2C=O.

Explanation:

Hello,

In this case, given that the hydrogen bondings are known as partial intermolecular interactions between a lone pair on an electron rich donor atom, particularly oxygen, and the antibonding molecular orbital of a bond between hydrogen and a more electronegative atom or group. Thus, among the options, C) formaldehyde, H2C=O, will exhibit hydrogen bonding since the lone pair of electrons of the oxygen at the carbonyl group, are able to interact with hydrogen (in the form of water).

Best regards.

8 0
3 years ago
In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce
Alexxandr [17]

Answer:

Velocity, u = 14.7 m/s

Explanation:

It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.

Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms

Using first equation of kinematics as :

v=u+at

In case of crash the final speed of the driver is, v = 0

0=u+at

-u=at

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u = 14.7 m/s

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8 0
3 years ago
Which of the following describes something an engineer would probably do
OLEGan [10]

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C. Research what has been done in the past to clean up oceanic oil

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The engineer being an innovator would probably have to dig through the past to see what has been done before him and in what way his technology is addressing the problem. If sees that his invention is unique, he would get a patent for his invention and then proceed to design the device. If he does not do this, he might just waste his whole duplicating an invention already made.

5 0
4 years ago
Read 2 more answers
Approximate temperature of a .7 mold sample of a gas at 1.2 ATM and volume of .170 L
faust18 [17]
Assuming you meant a 0.7 mole sample of a gas, we can approximate this by assuming that the gas is acting ideally, and use the ideal gas law PV=nRT. Using the following values:
P = 1.2 Atm
V = 0.170 L
n = 0.7 mol
R = 0.08206 L-atm/mol-K
We can rewrite the equation as: PV/nR = T
Plug in our values:
(1.2 atm)(0.170 L)/(0.08206*0.7 moles) = approximately 3.55 Kelvin = T
4 0
3 years ago
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