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3 years ago

Someone please help ????????

Mathematics

1 answer:

Zanzabum3 years ago

8 0

Answer:

use the distance formula,

by using it, prove the adjacent sides of the quadrilateral DEFG

hence, DEFG would be a rhombus

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The product of c and 2

Arlecino [84]

Answer:

c2?

Step-by-step explanation:

3 0

3 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

2. A bag contains 3 red, 4 white, and 5 blue marbles. Jason begins removing marbles from the bag at

galben [10]

Answer:

the total number of marbles are 12 and there are 3 colours so you divide 12 by 3

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3 years ago

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PLEASE HELP QUICK I AM IN A RUSH

Alekssandra [29.7K]

C because it simplifies to 0=0 which proves that it has infinite solutions!

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3 years ago

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First to answer gets brainliest

Grace [21]

Answer: 14
Square both sides, getting you
2x-3=25
Add 3 to both sides
2x=28
Divide both sides by 2
x=14

8 0

3 years ago

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