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Viktor [21]
3 years ago
9

HELP ME!!!!! Which choices are equivalent to the fraction below? CHECK ALL THAT APPLY.

Mathematics
2 answers:
Anton [14]3 years ago
6 0

Answer:

A. 1 and E. 9^0

Step-by-step explanation:

9/9 = 1

You can check this by actually solving the problem:

9^3 = 9*9*9 = 729

So...

729/729 = 1

Also, any number to the power of zero is one, so 9^0 is also a correct answer

slavikrds [6]3 years ago
3 0

Answer:

A and E

Step-by-step explanation:

9^3 / 9^3

Same number on top and bottom so 1 is an answer

look at the exponents, when dividing with exponents, you just subtract them, so it could also be 9^0, which is also 1

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What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is 
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}

Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70} 
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median. 

The value in the 8th slot is 54, so this is the median

Divide the sorted data set into two lists. I'll call them L and U 
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).

Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value. 

Therefore, Q3 = 62

Answer: 62</span>
4 0
3 years ago
The average person's
OLga [1]

Answer:

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Step-by-step explanation:

The answer would be 20 due to the fact that it would have to be 50 divided by 2.5 to get the answer of how many steps and 50 divided by 2.5 would equal 20

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Magdalena Figueroa's covered medical care bills for a recent illness were $8,440.00. Her major medical policy had a coinsurance
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