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Paul [167]
3 years ago
10

2. Describe how baking cake is an example of irriversible change.​

Chemistry
2 answers:
ZanzabumX [31]3 years ago
8 0
Answering so you can give the person the brainliest:)
aivan3 [116]3 years ago
6 0

Answer:

Baking a cake is a chemical and irreversible change, because once the raw materials are chemically converted during baking, one cannot recover the raw materials from the cake

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A sample of nitrogen gas is stored in a 592.2 mL flask at 108 kPa and 10.0°C. The gas is transferred to a 750.0 mL flask at 28.9
vfiekz [6]
According to Gases law, we know, 
PV/T = Constant

So, P₁V₁/T₁ = P₂V₂/T₂

Here, P₁ = 108 kPa
V₁ = 592.2 mL
T₁ = 10+273 = 283 K
P₂ = ?
V₂ = 750 mL
T₂ = 28.9+273 = 301.9

Substitute their values, 

108 * 592.2 / 283 = P₂ * 750 / 301.9
P₂ = 63957.6 * 301.9 / 283 * 750
P₂ = 19308799.44 / 212250
P₂ = 90.97 kPa

In short, Your Final Answer would be: 90.97 kPa

Hope this helps!
8 0
4 years ago
How was flame testing used
PIT_PIT [208]
The flame test is commonly used to identify different metal ions by how they get excited in the presence of a flame.
Typically a nichrome wire is dipped in a solution of metal cations and then presented to a flame. The flame emits a different color than normal, depending on the type of metal cation. Each metal ion gets excited by the flame and as the electrons change energy levels they emit a photon of light, thus changing the color. Since each metal cation has unique energy levels, the colors differ depend on the metal cation.

I hope this helps.
6 0
3 years ago
Acetylene gas (C2H2) is used in welding torches. When it reacts with oxygen, it produces
Vikki [24]

Mass C₂H₂ needed : 22.165 g

<h3>Further explanation</h3>

Reaction

2C₂H₂+ 5O₂ ⇒ 4CO₂ + 2H₂O

75.0 grams of CO₂ , mol CO₂ (MW=44 g/mol) :

\tt \dfrac{75}{44}=1.705

mol C₂H₂ :

\tt \dfrac{2}{4}\times 1.705=0.8525

mass C₂H₂ (MW=26 g/mol) :

\tt 0.8525\times 26=22.165~g

8 0
3 years ago
At what time will the pressure of SO₂Cl₂ decline to 0.50 its initial value? Express your answer using two significant figures.
QveST [7]

Answer: The time is 0.69/k seconds

Explanation:

The following integrated first order rate law

ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t

where

[SO₂Cl₂] concentration at time t,

[SO₂Cl₂]₀ initial concentration,

k rate constant

Therefore, the time elapsed after a certain concentration variation is given by:

t=\frac{ln[SO_{2}Cl_{2}]_{0} - ln[SO_{2}Cl_{2}]}{k}=\frac{ln\frac{[SO_{2}Cl_{2}]_{0}}{[SO_{2}Cl_{2}]} }{k}

We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:

p_{(SO_{2}Cl_{2})}V = n_{(SO_{2}Cl_{2})}RT

[SO_{2}Cl_{2}]= \frac{n_{(SO_{2}Cl_{2})}}{V}}=\frac{p_{(SO_{2}Cl_{2})}}{RT}}

In conclusion,

t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{p_{(SO_{2}Cl_{2})}} }{k}

for

p_{(SO_{2}Cl_{2})}=0.5p_{(SO_{2}Cl_{2})}_{0}

t=\frac{ln\frac{p_{(SO_{2}Cl_{2})}_{0}}{0.5p_{(SO_{2}Cl_{2})_{0}}} }{k}

t=\frac{ln\frac{1}{0.5} }{k}

t=\frac{ln(2)}{k}

t=\frac{0.69}{k}}

7 0
3 years ago
Copper (Cu) is often used for electrical wiring and cooking pans. However, iron (Fe) is much more common on Earth than copper. W
Sergeeva-Olga [200]
What iron gives in its abundance, it takes away in it's inability to really conduct heat and electricity well. There is enough copper around, if we are careful in its use, to make copper bottomed pots and pans. Of the three best conductors in the world (silver, gold and copper) only copper has enough around and can be inexpensively mined that we make use of it.

If you google dr. copper, you will find he is an economist as well. Copper measures the wealth of an economy by how much is used. So iron might be cheaper and more abundant, but copper will save you much more in trying to do something with it.
5 0
4 years ago
Read 2 more answers
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