Mg2+...because it loses 2 electron which is on its valence shell making it empty and making it have jst 2 shells. The radius calculated from d nucleus to the new valence shell is then smaller than that of Cl^- and k+
Option three, starfish is the correct answer since if you draw a line between it, it would be even!
The value of ΔG° at this temperature is -18034.18 J/mol
Calculation,
Given information
formation constant (Kf)= 1.7 × 
Universal gas constant (R) = 8.314 J/K• mol
Temperature = 25° C = 25 °C + 273 = 300 K
Formula used:
ΔG° = -RT㏑Kf
By putting the valur of R,T, Kf we get the value of ΔG°
ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 × 
ΔG° = -2494.2㏑ 1.7 ×
= -18034.18 J/mol
So, change in standard Gibbs's free energy is -18034.18 J/mol
Learn about formation constant
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Answer:
Chemical, Physical, Chemical, Chemical, Physical!!
Explanation:
I just did it correctly.
Answer:functional group (top row); sources in nature (bottom row)
Explanation: