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katovenus [111]
3 years ago
6

Is this right if not pls lmk what the correct answer is:)

Chemistry
1 answer:
trapecia [35]3 years ago
5 0

Answer:

It's right

Explanation:

Hopefully this helps!

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kari74 [83]

Answer:

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6 0
3 years ago
Someone help me please
Roman55 [17]

Answer:

i know it bro

Explanation:

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5 0
3 years ago
For each reaction below, use the drop-down menus to select which compound will form a precipitate. Note: It is possible that no
Dimas [21]

Answer:

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8 0
2 years ago
Calculate the fraction of lattice sites that are schottky defects for cesium chloride at its melting temperature (645oc). assume
baherus [9]
Answer : 7.87 X 10^{-6}.

Explanation : To find the fraction of schottky defects in the given lattice of CsCl,

we use the formula, \frac{N_{s} }{N}} = exp ( \frac{-Q_{s}}{2KT} )

on solving with the given values ,Q_{s}= 1.86 eV and T as 645 + 273 K and rest are the constants.

\frac{N_{s} }{N}} = exp ( \frac{-1.86 eV}{2 X (8.62 X 10^{-5}) X (645 +273)} )

we get the answer as 7.87 X 10^{-6}.
6 0
3 years ago
Read 2 more answers
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Ivahew [28]

Answer:

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Explanation:

7 0
3 years ago
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