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Strike441 [17]
2 years ago
12

D) hydrogen and sulfur Formed

Chemistry
1 answer:
mr Goodwill [35]2 years ago
3 0

Answer:

At high temperatures or in the presence of catalysts, sulfur dioxide reacts with hydrogen sulfide to form elemental sulfur and water. This reaction is exploited in the Claus process, an important industrial method to dispose of hydrogen sulfide.

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According to Niels Bohr, electrons travel around an atom's nucleus in well-defined orbits.
Bas_tet [7]

Answer: The answer is B

Explanation:

can i get brainliest?

5 0
2 years ago
Read 2 more answers
could you please explain operations with scientific notation using this example. 5 × 10³ + 4.3 × 10⁴ i dont understand how to so
TEA [102]

Explanation:

The scientific notation:

a\times10^k

where

1\leq a and k is integer.

We have the example:

(5\times10^3)+(4.3\times10^4)

You can write the numbers in a "normal" form:

5\times10^3=5\times1000=5000\\\\4.3\times10^4=4.3\times10000=43000

Make the sum:

5000+43000=48000

And next write it in the scientific notation:

48000=4\underbrace{8000}_{\leftarrow4}=4.8000\times10000=4.8\times10^4

<h3>Other method:</h3>

You can add numbers in scientific notation if the power of tens in both number is the same.

Therefore you must convert the first number:

5\times10^3=0.5\times10\times10^3=0.5\times10^4

Now, you can make the sum:

(5\times10^3)+(4.3\times10^4)=0.5\times10^4+4.3\times10^4=(0.5+4.3)\times10^4=4.8\times10^4

4 0
3 years ago
16. What are the reactants in the equation?
Dimas [21]
5. Iron and chlorine
4 0
3 years ago
Ammonia and oxygen react to form nitrogen and water.
Nata [24]

Answer:

A. 19.2 g of O2.

B. 3.79 g of N2.

C. 54 g of H2O.

Explanation:

The balanced equation for the reaction is given below:

4NH3(g) + 3O2(g) → 2N2+ 6H2O(g)

Next, we shall determine the masses of NH3 and O2 that reacted and the masses of N2 and H2O produced from the balanced equation.

This is illustrated below:

Molar mass of NH3 = 14 + (3x1) = 17 g/mol

Mass of NH3 from the balanced equation = 4 x 17 = 68 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96 g

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 from the balanced equation = 2 x 28 = 56 g

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = 6 x 18 = 108 g

Summary:

From the balanced equation above,

68 g of NH3 reacted with 96 g of O2 to produce 56 g of N2 and 108 g of H2O.

A. Determination of the mass of O2 needed to react with 13.6 g of NH3.

This is illustrated below:

From the balanced equation above,

68 g of NH3 reacted with 96 g of O2.

Therefore, 13.6 g of NH3 will react with = (13.6 x 96)/68 = 19.2 g of O2.

Therefore, 19.2 g of O2 are needed for the reaction.

B. Determination of the mass of N2 produced when 6.50 g of O2 react.

This is illustrated below:

From the balanced equation above,

96 g of O2 reacted to produce 56 g of N2.

Therefore, 6.5 g of O2 will react to produce = (6.5 x 56)/96 = 3.79 g of N2.

Therefore, 3.79 g of N2 were produced from the reaction.

C. Determination of the mass of H2O formed from the reaction of 34 g of NH3.

This is illustrated below:

From the balanced equation above,

68 g of NH3 reacted to 108 g of H2O.

Therefore, 34 g of NH3 will react to produce = (34 x 108)/68 = 54 g of H2O.

Therefore, 54 g of H2O were obtained from the reaction.

4 0
3 years ago
Were you in ms.secrihrst class in dutchtown middle.
IrinaVladis [17]

NO, why though this is a simple question lol!

4 0
3 years ago
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