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2 years ago

Thyroid hormone contains the mineral thyroid hormone contains the ________.

Chemistry

1 answer:

erica [24]2 years ago

8 0

Thyroid hormone contains the mineral iodine (option I). Details about thyroid hormone can be found below.

<h3>What is the thyroid hormone?</h3>

Thyroid hormone is the hormone produced by the thyroid gland of the body, which is a large butterfly-shaped endocrine gland situated on the front of the neck that produces various hormones.

The thyroid hormone is responsible for regulating metabolism, which controls the amount of calories burnt in a day.

One of the major minerals found in the thyroid is iodine. The thyroid gland absorbs iodine from the bloodstream, and then stores it to aid in the production of thyroid hormones.

Therefore, the thyroid hormone contains the mineral iodine.

Learn more about thyroid at: brainly.com/question/13856314

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A stock solution has a concentration of 1.5 M NaCl and is diluted to a 0.80 M solution with a volume of 0.10 L. What volume of t

ioda

Answer:

0.053 L is the volume of concentrated solution that was used

Explanation:

Let's determine the answer of this, by rules of three.

There is also a dilution formula.

Molarity is a sort of concentration that indicates the moles of solute in 1L of solution.

In 1 L of concentrated solution, there are 1.5 moles of NaCl

In 1 L of diluted solution, there are 0.80 moles.

The volume for the diluted solution is 0.10L

The rule of three will be:

1L of solution has 0.80 moles of solute

Then, 0.10L of solution must have (0.1 . 0.8)/1 = 0.08 moles

This moles came from the concentrated solution, and we know that in 1L of this solution we have 1.5 moles. Therefore the rule of three will be:

1.5 moles are in 1L of solution

0.08 moles were in (0.08 . 1L / 1.5) = 0.053 L (This is the volume of concentrated solution that was used)

Dilution formula is: M conc . Vol conc = M diluted . Vol diluted

1.5 M . Vol conc = 0.80 M . 0.10L

Vol conc = 0.80 M . 0.10L / 1.5M = 0.053L

4 0

3 years ago

Read 2 more answers

The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium

Ksenya-84 [330]

Answer:

The concentration is $C = 1.11 mol/L$

Explanation:

From the question we are told that

The absorbance is $A = 0.347$

The length is $l = 447 nm = 447 *10^{-7} \ cm$

Generally absorbance is mathematically represented as

$A = \epsilon* C * l$

where $\epsilon$ is the molar absorptivity of FeSCN2 with a value $\epsilon = 7.0*10^3 L/cm/mol$

and $C$ is the equilibrium concentration of FeSCN2

$C = \frac{A}{\epsilon * l }$

substituting values

$C = \frac{0.347}{7.0*10^{3} * 447 *10^{-7} }$

$C = 1.11 mol/L$

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3 years ago

The reaction for the combustion of methane is shown below. If 28.70g of methane

antiseptic1488 [7]

Omg hard question but it’s also amazing imma think about that question

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3 years ago

A magnesium atom has 2 valence electrons in its third shell.

likoan [24]

D. It will lose 2 electrons in order to become stable.

5 0

3 years ago

A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is

Vlada [557]

Answer:

$c=0.127\ J/g^{\circ} C$

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

$Q=mc\Delta T$

c is specific heat of the metal

$c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C$

So, the specific heat of metal is $0.127\ J/g^{\circ} C$ .

4 0

2 years ago