Write a function called is_present that takes in two parameters: an integer and a list of integers (NOTE that the first paramete
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#include <iostream>
#include <vector>
std::vector<int> v;
int main(int argc, char* argv[]) {
while(1) {
int temp;
std::cout << "\nEnter a number: ";std::cin>>temp;
if(temp<0) {
std::cout << "\nEven number(s) is/are:\n---------------------\n";
for(int i=0;i<v.size();i++) {
if(v.at(i)%2==0) std::cout << v[i] << " ";
else continue;
}
std::cout << std::endl;
break;
}else {
v.push_back(temp);
}
}
return 0;
}
