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3 years ago

Find the difference -5 3/10 - 2.5

Mathematics

1 answer:

Leviafan [203]3 years ago

8 0

Answer:

yes hauifbjrdjjskskjjfjjkwk DC

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Equation: -5 3/4- 3 1/2 Please help meh.

vampirchik [111]

Answer:

$-9\frac{1}{4}$

Step-by-step explanation:

$-5\frac{3}{4}-3\frac{1}{2}$

Step 1: Factor out the common term $-1$

$=-\left(5\frac{3}{4}+3\frac{1}{2}\right)$

Step 2: Add the whole numbers

$5 + 3 = 8$

Step 3: Combine the fractions:

$\frac{3}{4}+\frac{1}{2} = \frac{5}{4}\\\\=-\left(8+\frac{5}{4}\right)$

Step 4: Convert the improper fractions to mixed numbers

$\frac{5}{4} = 1\frac{1}{4}\\\\=-\left(8+1\frac{1}{4}\right)$

Step 5: Add the numbers

$8 + 1 =9 \\\\=-9\frac{1}{4}$

Therefore, the answer to the equation is $-9\frac{1}{4}$ in fraction, and decimal; $9.25$

4 0

3 years ago

a biker travel 5ft in .05seconds. At that same rate of speed , how far will the biker travel in 1minute?

Solnce55 [7]

Biker's rate is:

v = 5/0.5

v = 10 ft per sec

t = 1 min = 60 sec

d = the distance the biker travels in 1 minute

v = d/t

d = v*t

d = 10*60

d = 600 ft

The biker travels 600 feet in 1 minute

5 0

3 years ago

(please help quickly) Find the least common multiple of the following numbers.

IrinaK [193]

Answer:

1a. 156

1b. 147

2a. 45

2b. 84

3a. 160

3b. 108

4a. 210

4b.132

7 0

3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago

ANSWER ASAP

makvit [3.9K]

Answer:

-17 is less than -3.12345

Step-by-step explanation:

The larger the absolute value of the negative number, the less it is.

3 0

4 years ago

Find the difference -5 3/10 - 2.5​

Find the difference -5 3/10 - 2.5