Find the polynomial of least degree in standard form with the given roots:
x = 2, 3i
1 answer:
Answer:
x^3 - 2x^2 + 9x - 18.
Step-by-step explanation:
The complex roots occur in conjugate pairs so there are 3 roots 2, 3i and -3i.
So we have:
P(x) = (x - 2)(x - 3i)(x + 3i)
= (x - 2)(x^2 - 9i^2)
= (x - 2)(x^2 - 9*-1)
= (x - 2)(x^2 + 9)
= x^3 + 9x - 2x^2 - 18
= x^3 - 2x^2 + 9x - 18.
You might be interested in
(10 cm)(12 cm)(6 cm) = 720 cm^3
Answer:
Step-by-step explanation:
p=x(1-15/100)
p=x(100-15)/100
p=x(85/100)
p=0.85x
Answer:
That should be correct I checked over it
Step-by-step explanation:
A vertical stretch of 3, left 9 units, and up 6 units
