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2 years ago

Find the polynomial of least degree in standard form with the given roots: x = 2, 3i

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

4 0

Answer:

x^3 - 2x^2 + 9x - 18.

Step-by-step explanation:

The complex roots occur in conjugate pairs so there are 3 roots 2, 3i and -3i.

So we have:

P(x) = (x - 2)(x - 3i)(x + 3i)

= (x - 2)(x^2 - 9i^2)

= (x - 2)(x^2 - 9*-1)

= (x - 2)(x^2 + 9)

= x^3 + 9x - 2x^2 - 18

= x^3 - 2x^2 + 9x - 18.

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3 years ago

What property is this<br> 16+(c+17)=(16+6)+17

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2 years ago

Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of

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Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

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So,the amount in the account at 12% interest is $3400

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Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

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3 years ago

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