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german
3 years ago
10

What is the function of enter key​

Physics
2 answers:
ICE Princess25 [194]3 years ago
8 0

Answer:

The enter key is a computer innovation, which in most cases causes a command line, window form, or dialog box to operate its default function. This is typically to finish an "entry" and begin the desired process, and is usually an alternative to clicking an OK button.

garri49 [273]3 years ago
4 0

Answer:

what key

Explanation:

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jolli1 [7]

Answer:

Pressure=Force/Area

Explanation:

6 0
2 years ago
Read 2 more answers
Moving along the elevtromagnetic spectrum from low frequency to high frequency, what , if anything, happens to the wavelength?
jenyasd209 [6]

Explanation:

the wavelengths get shorter

3 0
2 years ago
An object has a position given by r = [2.0 m + (5.00 m/s)t] i^ + [3.0m−(2.00 m/s2)t2] j^, where all quantities are in SI units.
makkiz [27]

Answer:

Acceleration of the object is 4\ m/s^2.

Explanation:

It is given that, the position of the object is given by :

r=[2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j

Velocity of the object, v=\dfrac{dr}{dt}

Acceleration of the object is given by :

a=\dfrac{d^2r}{dt^2}

a=\dfrac{d^2}{dt^2}([2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j)

Using the property of differentiation, we get :

a=\dfrac{d^2r}{dt^2}=-4\ m/s^2

So, the magnitude of the acceleration of the object at time t = 2.00 s is 4\ m/s^2. Hence, this is the required solution.

5 0
2 years ago
The __________ of exercise determines the health and fitness benefit of the exercise. A. frequency B. intensity C. time D. type
MariettaO [177]

Answer:

c- Time

Explanation:

The time will tell depending on the person who is exercising, the rate of time, the  workout time. & limits on weights....

6 0
2 years ago
Read 2 more answers
Olaf is standing on a sheet of ice that covers the football stadium parking lot in Buffalo, New York; there is negligible fricti
Bas_tet [7]

Answer:

v = 0.059 m/s

Explanation:

To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:

mv_{1i}+Mv_{2i}=(m+M)v  (1)

m: mass of the ball = 0.400kg

M: mass of Olaf = 75.0 kg

v1i: initial velocity of the ball = 11.3m/s

v2i: initial velocity of Olaf = 0m/s

v: final velocity of Olaf and the ball

You solve the equation (1) for v and replace the values of all variables:

v=\frac{mv_{1i}}{m+M}=\frac{(0.400kg)(11.3m/s)}{0.400kg+75.0kg}=0.059\frac{m}{s}

Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s

3 0
2 years ago
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