Answer:200j
Explanation:
mass(m)=1kg
Velocity(v)=20m/s
Kinetic energy=(m x v^2) ➗ 2
Kinetic energy =(1 x 20^2) ➗ 2
Kinetic energy=(1 x 20 x 20) ➗ 2
Kinetic energy=400 ➗ 2
Kinetic energy =200j
Answer:
The force of gravity at the shell will be extremely great on me due to the huge mass collapsed into the small radius.
<em>At the center of the shell, the gravitational forces all around should cancel out, giving me a feeling of weightlessness; which will be a lesser force compared to that felt while standing on the shell.</em>
<em></em>
Explanation:
For the collapsed earth:
mass = 5.972 × 10^24 kg
radius = 1 ft
according to Newton's gravitation law, the force of gravity due to two body with mass is given as
Fg = GMm/
Where Fg is the gravitational force between the two bodies.
G is the gravitational constant
M is the mass of the earth
m is my own mass
R is the distance between me and the center of the earths in each case
For the case where I stand on the shell:
radius R will be 1 ft
Fg = GMm/
Fg = GMm
For the case where I stand stand inside the shell, lets say I'm positioned at the center of the shell. The force of gravity due to my mass will be balanced out by all other masses around due to the shell of the hollow earth. This cancelling will produce a weightless feeling on me.
Answer:
(a). The distance is 49.79 m.
(b). The speed of the ball is 24.39 m/s.
Explanation:
Given that,
Speed = 20 m/s
Angle = 40°
Height = 22 m
Time = 3.25 sec
(a). We need to calculate the distance
Using formula of distance

Put the value into the formula


(b). We need to calculate the horizontal velocity
Using formula of velocity

Put the value into the formula


We need to calculate the vertical velocity
Using equation of motion

Put the value into the formula


Negative sign shows the opposite direction.
We need to calculate the speed of ball
Using formula of speed



Hence, (a). The distance is 49.79 m.
(b). The speed of the ball is 24.39 m/s.
Answer:
The magnitude of the resistive force exerted by the water is
newtons.
Explanation:
By First and Second Newton's Law, the resistive force exerted by the water on the cruise ship has the same magnitude of forward thrust, with which it is antiparallel to. The equation of equilibrium for the luxury liner is:
(Eq. 1)
Where:
- Forward trust, measured in newtons.
- Resistive force exerted by the water, measured in newtons.
From (Eq. 1), we get that: (
)


The magnitude of the resistive force exerted by the water is
newtons.