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adoni [48]
3 years ago
11

Parents of students at a middle school

Mathematics
2 answers:
Rasek [7]3 years ago
7 0
The answer is B 319 parents
Contact [7]3 years ago
6 0

Answer:

<em>(B). 319 </em>

Step-by-step explanation:

\frac{42}{60} = \frac{x}{456}

\frac{7}{10} = \frac{x}{456}

x = \frac{7*456}{10} ≈ <em>319</em>

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Solve: 2x + 3 = -1 im not that good at algebra type questions
IgorLugansk [536]


2x+3=-1         /-3

2x=-4        /:2

x=-2

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%2064%2F4" id="TexFormula1" title="\sqrt{x} 64/4" alt="\sqrt{x} 64/4" align="abs
ozzi

Answer: =16\sqrt{x}

Step-by-step explanation:

\sqrt{x}\frac{64}{4}=16\sqrt{x}

8 0
3 years ago
Can some one help I forgot how to do 0.6 divided by 12.9. Plzzzzz anyone hellppppppp
Katyanochek1 [597]

The answer to your question is 0.046511627906

Explanation:

Simple, use a calculator to answer your question.

3 0
2 years ago
Find a and b. Help me please.
Yakvenalex [24]
Hi there. Actually, the image that you have provided us with is a little bit blurry so, if you can make the image a little bit clearer, then I can help you with this question.
Thanks.
4 0
3 years ago
A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yield
Leno4ka [110]

Answer:

0.762 = 76.2% probability that this shipment is accepted

Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17 randomly selected pens

This means that n = 17

(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is P(X \leq 2) when p = 0.1. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167

P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315

P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762

0.762 = 76.2% probability that this shipment is accepted

8 0
4 years ago
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