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2 years ago

Which equation js equivalent to 4(2x-3)-3(x-4)+7x=6?

Mathematics

1 answer:

zimovet [89]2 years ago

7 0

Standard form: 12x=6

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Help<br> I’ll give a lot of credits

jenyasd209 [6]

Answer:

52.5

Step-by-step explanation:

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2 years ago

The price of a 40-inch television is $268 plus 8% sales tax rate. What is the amount of the sales tax for the television, in dol

Harlamova29_29 [7]

$268.00 base price
8% is $21.44
Total with tax $289.44

3 0

2 years ago

erica is going to use the following ingredients to make pancakes for breakfast 2 1/2 cups of flour ,1/2 cups of sugar

nlexa [21]

I don't get it. Whats the question???

6 0

3 years ago

A 11 gram sample of substance that's used to treat thyroid disorders s has a k-value of 0.1247

Ira Lisetskai [31]

Answer:

You don't have a question but I'll answer what I can.

half-life = natural log (.5) / k

half-life = -.693147 / .1247

half-life = 5.561106656

It seems you did not express the k-value properly.

1) A k-value should have a negative value.

2) A k-value should also have units.

For example, the k-value of tungsten 181 is

-0.005723757 / days

Step-by-step explanation:

8 0

3 years ago

According to the Oxnard College Student Success Committee report in the previous year, we believe that 18% of students struggle

gladu [14]

Answer:

A sample size of 392 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

18% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class.

This means that $\pi = 0.18$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

You would like to be 99% confident that your estimate is within 5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.05. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.05 = 2.575\sqrt{\frac{0.18*0.82}{n}}$

$0.05\sqrt{n} = 2.575\sqrt{0.18*0.82}$

$\sqrt{n} = \frac{2.575\sqrt{0.18*0.82}}{0.05}$

$(\sqrt{n})^2 = (\frac{2.575\sqrt{0.18*0.82}}{0.05})^2$

$n = 391.5$

Rounding up:

A sample size of 392 is required.

8 0

3 years ago