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VARVARA [1.3K]
3 years ago
10

What is the answer to this equation? Must solve for x. x+5=12x−4

Mathematics
2 answers:
natulia [17]3 years ago
8 0

Answer:

x = 9/11

Step-by-step explanation:

x + 5 = 12x - 4

Subtract x from both sides

x + 5 - x = 12x - x - 4

        5   = 11x - 4

Add 4 to both sides

      5+ 4 = 11x - 4 + 4

            9 = 11x

Divide both sides by 11

         9/11 = 11x/11

          9/11 = x

x = 9/11

AleksAgata [21]3 years ago
7 0

Answer:

x  -  12x =  - 4 - 5 \\ 11x = 9 \\ x =  \frac{9}{11}  \\

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A rectangular box is designed to have a square base and an open top. The volume is to be 500in.3 What is the minimum surface are
mr_godi [17]

The minimum surface area that such a box can have is 380 square

<h3>How to determine the minimum surface area such a box can have?</h3>

Represent the base length with x and the bwith h.

So, the volume is

V = x^2h

This gives

x^2h = 500

Make h the subject

h = 500/x^2

The surface area is

S = 2(x^2 + 2xh)

Expand

S = 2x^2 + 4xh

Substitute h = 500/x^2

S = 2x^2 + 4x * 500/x^2

Evaluate

S = 2x^2 + 2000/x

Differentiate

S' = 4x - 2000/x^2

Set the equation to 0

4x - 2000/x^2 = 0

Multiply through by x^2

4x^3 - 2000 = 0

This gives

4x^3= 2000

Divide by 4

x^3 = 500

Take the cube root

x = 7.94

Substitute x = 7.94 in S = 2x^2 + 2000/x

S = 2 * 7.94^2 + 2000/7.94

Evaluate

S = 380

Hence, the minimum surface area that such a box can have is 380 square

Read more about surface area at

brainly.com/question/76387

#SPJ1

5 0
2 years ago
Use the quadrant system to find the area of the polygon. A. 52 square units B. 45 square units C. 36 square units D. 38 square u
Alona [7]

Answer:

its c 36 square units


Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
HELP!!!!!!!!!!!
erica [24]
Your answer would be (b.) because -2+-3=-5

3 0
3 years ago
Read 2 more answers
Explain the special pattern for sketching a parabola
Lady bird [3.3K]

Answer:

the parabola can be written as:

f(x) = y = a*x^2 + b*x + c

first step.

find the vertex at:

x  = -b/2a

the vertex will be the point (-b/2a, f(-b/2a))

now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.

The next step is to see if we have real roots by using the Bhaskara's equation:

x =  \frac{-b +-\sqrt{b^2 -4ac} }{2a}

Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.

If you do not have any real roots, you can feed into the parabola some different values of x around the vertex

for example at:

x =  (-b/2a) + 1 and x =  (-b/2a) - 1

those two values should give the same value of y, and now you can connect the vertex with those two points.

If you want a more exact drawing, you can add more points (like x =  (-b/2a) + 3 and x =  (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.

8 0
3 years ago
If the following is a monomial, write it in standard form.
Sati [7]

Answer:

Monomial; Standard form: 18a^2b^2

Step-by-step explanation:

6 {a}^{2} 3 {b}^{2}  = 6 \times 3 {a}^{2}  {b}^{2}  = 18{a}^{2}  {b}^{2}  \\

8 0
3 years ago
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