Answer:
is the liberation of electrons from an electrode by virtue of its temperature
Explanation:
Answer:
You're supposed to measure the distance from X to the end of vector 5 using the appropriate scale, and measure the angle (counterclockwise from X) using a protractor.
Mathematically:
x = [83cos90+55cos141+69cos229+41cos281+61co... cm = -27 cm
y = [83sin90+55sin141+69sin229+41sin281+61si... cm = 55 cm
so d = √(x² + y²) = 61 cm
and Θ = arctan(55/-27) = -64º +180º (to get into QII) = 116º
Explanation:
Explanation:
As we know that
time = distance/speed
The time used for firs half of the trip was
(1 mi)(12 mi/hour) = 1/12 hours = 5 minutes
The last half of the trip will took 10 minutes, 1/6 hour.
Speed = distance/ time
(1 mil) = (1/6h) = 6 mil/h
so the speed for last half of the trip was = 6mph
the average speed was
(2mil)(1/4 hour) = 8 mil/hour
So the ling's average speed was 8mph.
The point has to be validated I believe
Answer:
D. The net force on an object applied over a distance
Explanation:
Work can be defined as the product of force multiplied by a distance
Where
F = force [Newtons]
d = distance = [meters]
Therefore:
Work = F * d
Work in units of Joules [J]