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Kaylis [27]
3 years ago
11

A through shaped tank is located 3 meters underground (The top of the tank is 3 meters away from ground level.) The dimensions o

f the tank are: height h = 5 meters, length c = 10 meters, base width a = 4 meters and top width b = 8 meters. If the tank is completely full, find the work done in pumping all the water out of the tank to ground level.
Physics
1 answer:
vovangra [49]3 years ago
4 0

Answer:

900kJ

Explanation:

Work done hereis lifting that water mass on to the surface level

v = volume of the tank

d= density of water (1000kg/m3)

g = gravotational acceleration

workdone=Weight * distance

                = (v*d*g)*distance

                ==((\frac{8+4}{2} )*5*10)*1000*10*3\\=900000J\\=900kJ

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Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

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- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

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3 years ago
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Ten quantities that are pure numbers​
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A frictionless piston–cylinder device contains 7 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin
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Answer: -1038.8 kJ

Explanation:

From the question, we can see that PV^n = constant. And as such, we can deduce that it is a polytropic process. Thus, we can use the polytropic work equation to calculate the needed work input.

from the question we were given

Mass of nitrogen, m = 7kg

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W = [m * R * T2 - T1] / 1 - n

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W = 415.52 / -0.4

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