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BartSMP [9]
3 years ago
15

A cannonball is launched with an initial speed of 20 m/s. Calculate the maximum height the ball could reach.

Physics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

During its trajectory the cannon ball will have kinetic and potential energy

E = KE + PE

The maximum value of PE will occur when the cannon ball was fired straight up - for other trajectories PE will be less because of translational KE

So E = M g h = 1/2 M v^2    for maximum height

h = v^2 / (2 * g) = 400 / (2 * 9.8) = 20.4 m

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Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy. We will take the point where the Falcon reaches the speed of 69 (m/s), as the point where the potential energy is zero, i.e. it will be the reference point.

At the reference point all potential energy has been transformed into kinetic energy, therefore the kinetic energy can be calculated.

E_{k}=0.5*m*v^{2} \\ where:\\v = velocity = 69 [m/s]\\m = mass = 480[g] = 0.480[kg]\\E_{k} = kinetic energy [J]\\E_{k} =0.5*0.48*(69)^{2} \\E_{k} =1142.64[J]

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E_{p}=m*g*h\\ E_{p}=E_{k} \\therefore\\h= E_{p}/(m*g)\\h= 1142.64/(.48*9.81)\\h=242[m]

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