Question

A SPARK PLUG IN AN AUTOMOBILE ENGINE CONSISTS OF TWO

Answer 1

Answer:

Electric potential, $V=3.52\times 10^{12}\ volts$

Explanation:

It is given that,

The magnitude of electric field, $E=4.7\times 10^7\ V/m$

Distance between automobile engines that consists of metal conductors, $d = 0.75\ mm = 7.5\times 10^4\ m$

Let V is the magnitude of the potential difference between the conductors. The relation between the electric field and the electric potential is given by:

$V=E\times d$

$V=4.7\times 10^7\ V/m \times 7.5\times 10^4\ m$

$V=3.52\times 10^{12}\ volts$

So, the magnitude of the potential difference between the conductors is $3.52\times 10^{12}\ volts$. Hence, this is the required solution.