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DochEvi [55]
4 years ago
9

A SPARK PLUG IN AN AUTOMOBILE ENGINE CONSISTS OF TWO

Physics
1 answer:
kirill [66]4 years ago
6 0

Answer:

Electric potential, V=3.52\times 10^{12}\ volts

Explanation:

It is given that,

The magnitude of electric field, E=4.7\times 10^7\ V/m

Distance between automobile engines that consists of metal conductors, d = 0.75\ mm = 7.5\times 10^4\ m

Let V is the magnitude of the potential difference between the conductors. The relation between the electric field and the electric potential is given by:

V=E\times d

V=4.7\times 10^7\ V/m \times 7.5\times 10^4\ m

V=3.52\times 10^{12}\ volts

So, the magnitude of the potential difference between the conductors is 3.52\times 10^{12}\ volts. Hence, this is the required solution.

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Summarize one or more impacts of the physics of matter on aviation operations.
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Answer:

Answered

Explanation:

impacts of the physics of matter on aviation operations.

Thrust, drag and lift.

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Drag:

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3 0
4 years ago
A dvd drive has a maximum speed of 72000 revolutions per minute. if a dvd has a diamter of 12 what is the linear speed
Brilliant_brown [7]
The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
P=2\pi.R
Know recall that:
v=\frac{d}{t}
We now need to know how much distance is traveled during a minute or 60 seconds:
D=7200\times 2\pi\times R
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v=\frac{7200\times2\pi\times R}{60}
\\
R=\frac{12}{2}=6

v\approx 4523.89 \frac{units}{second}
Where the distance units were named units as the length unit is not specified in this exercise.<span />
7 0
4 years ago
An elevated water tank holds 1 million gallons of water. Determine the force (in lbf) that the tower structure must be able to w
bixtya [17]

Answer:

8,345,925 lb-f

Explanation:

We know pressure P = F/A = ρgh ⇒ F = ρghA = ρgV

F = ρgV where F = force, ρ = density of water = 1000 kg/m³ , g = acceleration due to gravity = 9.8 m/s² and V = 1 × 10⁶ gallons = 1 × 10⁶ gallons × 1m³/264.2 gallons = 3785 m³

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We now convert Newtons to pound-force.

1 N = 0.225 lb-f

So, F = 37,093,000 N = 37,093,000 N × 0.225 lb-f/1 N = 8,345,925 lb-f

So, the tower must be able to withstand 8,345,925 lb-f

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