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sveta [45]
3 years ago
7

In a crash test, a 2,500 kg car hits a concrete barrier at 13 m/s2 calculate the amount of force at which the car strikes the ba

rrier. The car strikes the barrier with a force of?
Physics
2 answers:
Marta_Voda [28]3 years ago
8 0

Answer:

32500N

Explanation:

Data obtained from the question include:

m (mass) = 2500 kg

a (acceleration) = 13 m/s2

F (force) =?

Force is the product of mass and acceleration. It is represented mathematically as:

Force = mass x acceleration

F = m x a

With the above formula, the force with which the car strikes the barrier can be obtained as follow:

F = m x a

F = 2500 x 13

F = 32500N

Therefore, the car will strike the barrier with a force of 32500N

Reil [10]3 years ago
5 0

3250N, Third law

Explanation:

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3 years ago
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6 0
3 years ago
Read 2 more answers
A 35.8 kg box initially at rest is pushed 2.38 m along a rough, horizontal floor with a constant applied horizontal force of 108
tiny-mole [99]

Answer:

The work done by the applied force is 259.22 J.

Explanation:

The work done by the applied force is given by:

W = F*d

Where:

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d: is the distance = 2.38 m  

Hence, the work is:

W = F*d = 108.915 N*2.38 m = 259.22 J

Therefore, the work done by the applied force is 259.22 J.

I hope it helps you!                                                

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