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MatroZZZ [7]
3 years ago
8

You randomly choose two bills from your wallet. What is the probability that they are both $20 bills. There are two 20's, one 10

, two 5's, and one 1.
Mathematics
2 answers:
Softa [21]3 years ago
7 0

Answer:

2/6 or 33.33%

Explanation:

There are 6 numbers all together and 2 of them are 20$.As a fraction this would look like 2/6. 2/6 is also 33.33% of the wallet and its also the probability of pulling out a $20 bill

weqwewe [10]3 years ago
6 0

Answer:

1/15

Step-by-step explanation:

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19 Select the decimal that is equivalent to 27 Choose 1 answer: А 0.626 B 0.626 C 0.703 0.703 E None of the above ​
Natali [406]

Answer:

I am pretty sure it is none of the above but I don’t know for sure

7 0
2 years ago
Given the function f(x)=4|x-5|+3 for what values of x is f(x)=15
Andreyy89

Answer:

  {2, 8}

Step-by-step explanation:

We want to find x for ...

  15 = 4|x -5| +3

  12 = 4|x -5| . . . . subtract 3

  3 = |x -5| . . . . . . divide by 4

  ±3 = x -5 . . . . . . show the meaning of absolute value

  5 ±3 = x = {2, 8} . . . . . add 5

The values of x for which f(x) = 15 are 2 and 8.

3 0
3 years ago
Wesley and Lincoln went fishing. Wesley caught a fish 15 3/16 inches long and Lincoln caught a fish 12 3/4 inches long. How many
Arlecino [84]

Answer:

2 7/16 inches longer

Step-by-step explanation:

15 3/16 - 12 3/4= 243/16 - 51/4 = 243/16 - 204/16= 39/16 inches longer

39/16=2 7/16 inches longer

8 0
2 years ago
What is another way to write this number 300+70+5/10+8/100
trasher [3.6K]
The answer is 370.58
5 0
3 years ago
Read 2 more answers
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
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