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Sphinxa [80]
3 years ago
15

PLS HELP I WILL DO ANYTHING PLS

Mathematics
1 answer:
olganol [36]3 years ago
4 0
447 with 0 remainder
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What is the simplified expression for the expression below?<br><br> 4(x + 8) + 5(x – 3)
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4x + 8 + 5x - 3 or 9x + 5 depending on the awnser choices

Please GIB BRAINLIST I WANT SO BAD!!!!
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Can anyone answer these for me please?
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(2) is 1
because of pemdas
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4 years ago
Read 2 more answers
Marshall evaluates the expression 15.3 - 7.9 and gets an answer of 7.4.
creativ13 [48]

Answer:

yes

Step-by-step explanation:

15.3-7.9=7.4

7 0
4 years ago
I need help please. I got these 2 wrong
horrorfan [7]

The domain is {-9,-4,3,9} and the range is {2}.


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3 years ago
Suppose that a random sample of size 64 is to be selected from a population with mean 40 and standard deviation 5. (a) What are
Dmitriy789 [7]

Answer:

a)  \bar X \sim N(40,\frac{5}{\sqrt{64}}=0.625)

b) P(39.6 \leq \bar X \leq 40.4)=0.4778

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

X \sim N(\mu=40,\sigma=5)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

(a) What are the mean and standard deviation of the sampling distribution?

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(40,\frac{5}{\sqrt{64}}=0.625)

(b) What is the approximate probability that x will be within 0.4 of the population mean μ? (Round your answer to four decimal places.) P =

So for this case we want this probability:

P(40-0.4 \leq \bar X \leq 40+0.4)= P(39.6 \leq \bar X \leq 40.4)

And for this case we can use the z score given by this formula:

Z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this concept we got this:

P(\frac{39.6 -40}{\frac{5}{\sqrt{64}}} \leq \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}} \leq \frac{40.4 -40}{\frac{5}{\sqrt{64}}})

P(-0.64 \leq Z \leq 0.64) =P(z

8 0
3 years ago
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