Answer:
3
Step-by-step explanation:
there are 15 pieces of candy and 5 people, so all you have to do is divided 15 by 5 which gives you 3 meaning each person gets 3 pieces.
Ur perpendicular line will have -1 as the slope
y - y1 = m(x - x1)
slope(m) = -1
(2,5)...x1 = 2 and y1 = 5
now sub
y - 5 = -1(x - 2) can be written like : y - 5 = -(x - 2)
Answer:
-31/6
Step-by-step explanation:
77+2(3x-5)=8-3(2x+1)
77+6x-10=8-6x-3
77-10+6x=8-3-6x
67+6x=5-6x
67+6x-(-6x)=5
67+6x+6x=5
67+12x=5
12x=5-67
12x=-62
x=-62/12
simplify
x=-31/6
Answer:
R3 <= 0.083
Step-by-step explanation:
f(x)=xlnx,
The derivatives are as follows:
f'(x)=1+lnx,
f"(x)=1/x,
f"'(x)=-1/x²
f^(4)(x)=2/x³
Simialrly;
f(1) = 0,
f'(1) = 1,
f"(1) = 1,
f"'(1) = -1,
f^(4)(1) = 2
As such;
T1 = f(1) + f'(1)(x-1)
T1 = 0+1(x-1)
T1 = x - 1
T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2
T2 = 0+1(x-1)+1(x-1)^2
T2 = x-1+(x²-2x+1)/2
T2 = x²/2 - 1/2
T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3
T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3
T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)
Thus, T1(2) = 2 - 1
T1(2) = 1
T2 (2) = 2²/2 - 1/2
T2 (2) = 3/2
T2 (2) = 1.5
T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)
T3(2) = 4/3
T3(2) = 1.333
Since;
f(2) = 2 × ln(2)
f(2) = 2×0.693147 =
f(2) = 1.386294
Since;
f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).
Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,
Since;
f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2
Finally;
R3 <= |2/(4!)(2-1)^4|
R3 <= | 2 / 24× 1 |
R3 <= 1/12
R3 <= 0.083
Answer:
2.345×0.023
2.345..........3 decimal point
0.023........3 decimal point
2345
× 23 1. first we change it whole number for multiply.
···················· 2.count the decimal point.here 6 decimal points are there.
+ 7 0 3 5 3.we got the answer 53935.here only 5 digits are there.
4 6 9 0 0 4.now we add one zero backside 053935
····························5 . final answer is 0.053935
5 3 9 3 5
···························
answer is =0.053935
Step-by-step explanation:
