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3 years ago

11

The question is in the picture. You will get 15 points and brainiest if you answer it. I need it asap as this is due in 12 minut

es.

1 answer:

victus00 [196]3 years ago

6 0

Answer:

constant proportanality is 12 k=12

Step-by-step explanation:

because 5 time 12= 60 and it keep going and going

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Find the radius of the circle with equation x²+y²+8x+8y+28=0

galina1969 [7]

<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^{2}+y^{2}+8x+8y+28=0$

So, solving we have:

$x^{2}+y^{2}+8x+8y=-28$

$(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4$

$(x^2-(-4))+(y^2-(-4))=4$

Now, we have that:

$h=-4\\k=-4\\r=\sqrt{4}=2$

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0

3 years ago

40 PIONTS!!! HELP PLZ ANSWER THE QUESTIONS (IF YOU DONT ASWER THE QUETIONS THEN I WILL REPORT YOU)

allochka39001 [22]

Answer:

quadrant 1.

Step-by-step explanation:

A:(9,3)

B:(7,5)

C:(5,2)

Hope this helped you.

4 0

3 years ago

The number of 500g amount in 1 kg is

Y_Kistochka [10]

Answer:

500 g = 0.5 kg

Step-by-step explanation:

1 kg = 1000 g

500 g = 0.5 kg

3 0

3 years ago

Multiply? I don't know how to do this o.o<br><br> (X+4√2) (x-4√2) (x-3i)

Korolek [52]

Answer:

$x^{3} -(3i) \; x^{2} -32x + 96 i$ .

Step-by-step explanation:

Notice that the first two factors are in the form $(x-a)(x+a)$ , which is equal to $(x^{2} - a^{2})$ . Start by combining and expanding these two factors:

Let $a = 4\sqrt{2}$ .

$a^{2} = 16 \times 2 = 32$ .

$(x + a) (x - a) = x^{2} - a^{2} = x^{2} -32$ .

This expression can now be expressed as $(x^{2} - 32)(x - 3i)$ . $i$ stands the unit imaginary number, where $i^{2} = -1$ . Unless $i$ is raised to a certain power other than $1$ , it can be treated just like a constant.

Expand this expression using FOIL:

$\begin{aligned}&(x^{2} - 32)(x - 3i)\\=&\underbrace{x^{2}\cdot x}_{\verb!F!} +\underbrace{(x^{2})(-3i)}_{\verb!O!} + \underbrace{(-32)x}_{\verb!I!} + \underbrace{(-32)(-3i)}_{\verb!L!}\\=& x^{3} -(3i)x^{2}-32x + 96i \end{aligned}$ .

6 0

3 years ago

⎧ y=2x+3 y=−3x+3

masha68 [24]

What exactly do u want us to do?

4 0

3 years ago