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svp [43]
2 years ago
9

Use the distributive property to rewrite the expression in factored form. 15g−40

Mathematics
2 answers:
Vaselesa [24]2 years ago
6 0

Answer:

5(3g-8)

Step-by-step explanation:

First find the greatest common factor of 15 and 40

It is 5 so              15/5 =3       40/5= 8

5(3g-8)

ELEN [110]2 years ago
3 0

Answer:

5(3g-8)

Step-by-step explanation:

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#4 math homework help needed. Thank you
liubo4ka [24]

Answer:

C. -1

Step-by-step explanation:

f(x) = 2/ (-x-1)

As we can see, f(x) is a fraction with two components: numerator (2) and denominator (-x-1).

According to the theorem, the fraction only exists when its denominator is different from 0.

So that in this situation, (-x-1) has to be different from 0

- x - 1 ≠0

=> - x≠ 1

=> x ≠ -1

So that if x = -1, (-x-1) = 0, making the fraction not exist.

So the input is not allowed is x = -1

5 0
3 years ago
If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun
AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

               Nonsmokers      Light Smoker     Heavy smoker      Total

Men                        303                     35                           37        375

Women                   413                     31                            45        489

Total                        716                     66                           82        864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

82C2=\frac{82!}{2!(82-2)!}=3321

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

864C2=\frac{864!}{2!(864-2)!}=372816

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908

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3 years ago
A guidance counselor is studying test anxiety in freshman students. A random sample of 972 high school freshmen finds that 219 o
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Answer:

The answer is B.

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