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Allisa [31]
3 years ago
7

Please Read the Attachment below

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

\frac{a -30y}{a^2 -100y^2} - \frac{10y}{10ay -a^2}

                               =\frac{a-30y}{a^2 -(10y)^2} - \frac{10y}{-a(a -10y)}\\\\=\frac{a-30y}{(a -10y)(a+10y)} + \frac{10y}{a(a -10y)}\\\\=\frac{a(a-30y) +10y(a+10y)}{a(a -10y)(a+10y)} \\\\=\frac{a^2 - 30ay +10ay +100y^2}{a(a-10y)(a+10y)}\\\\=\frac{a^2 - 20ay +100y^2}{a(a-10y)(a+10y)}\\\\=\frac{(a-10y)^2}{a(a-10y)(a+10y)}\\\\=\frac{(a-10y)}{a(a+10y)}

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