To calculate the frequency change of a moving source, the formula used is:
f = c*fo/(c+Vs)
where:
f = frequency observed
c = speed of sound
Vs = speed of source (positive if it's moving away from observer and negative if it is moving towards the observer)
fo = emitted frequency of the source
f = 342*652/(342-5)
f = 661.67 Hz or 662 Hz --> FINAL ANSWER
These pattern of lines<span>, sometimes referred to as </span>electric field lines<span>, point in the direction that a positive test charge would accelerate if placed upon the </span>line<span>. As such, the </span>lines<span> are directed away from positively charged source charges and toward negatively charged source charges.</span>
Explanation:
given that the raven flies south for
time= 10 sec
speed= 10km/s
we know that speed=distance/time
distance=speed*time
distance=10*100
distance=1000m
distance=1km
also flies
distance=0.5km = 500m
time= 50 sec
speed= distance/time
speed=500/50
speed= 10m/s
speed= 0.01km/s
The average speed of an object is defined as the distance traveled divided by the time elapsed.
average speed= (1000+500)/10+50
average speed= (1500)/60
average speed= 25m/s
average velocity= (10km/s+0.01km/s)/2= 10.01/2= 5.005km/s
Answer:
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
Explanation:
For laminar flow between two parallel horizontal plates, the volumetric flow per metre of width is given as
q = (2h³/3μ) (ΔP/L)
h = hydraulic depth = 4mm/2 = 2mm = 0.002 m
μ = viscosity of oil (SAE 30) at 15.6°C = 0.38 Pa.s
(ΔP/L) = 26 KPa/m = 26000 Pa/m
q = (2h³/3μ) (ΔP/L)
q = (26000) × (2(0.002³)/(3×0.38))
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
I believe the answer is C