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Marina CMI [18]
3 years ago
13

A particle moves along the x axis. Its position is given by the equation

Physics
1 answer:
krok68 [10]3 years ago
3 0

The position of the particle when it changes direction is x = 3.0 m

Explanation:

The position of the particle is given by the equation

x(t)=2.4+2.9t-3.5t^2

In order to determine its position when it changes direction, we need to  find the time t at which the velocity of the particle becomes zero.

The velocity of the particle si given by the derivative of the position, therefore:

v(t)=\frac{dx}{dt}=2.9-2\cdot 3.5t^{2-1}=2.9-7t

The velocity is zero when:

v(t)=0=2.9-7t\\7t=2.9\\t=\frac{2.9}{7}=0.41 s

And therefore, the position at t = 0.41 s is

x(0.41)=2.4+2.9(0.41)-3.5(0.41)^2=3.0 m

Learn more about position and velocity:

brainly.com/question/5248528

#LearnwithBrainly

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Frank has a sample of steel that has a mass of 80 grams if the density is 8g/cm3 what is the volume
nikklg [1K]
Density is mass divided by volume. rho=m/v. So, v=m/rho. In frank's case this is 80/8 = 10 cm^3.
7 0
3 years ago
An object moves 2.5 m. This is an example of a _______. Question 3 options: direction distance velocity speed
Hitman42 [59]
Distance, since distance represents how far something has travelled, which would be in our case 2.5m.
5 0
3 years ago
Read 2 more answers
An airplane flies at 40 m/s at an altitude of 50 meters. The pilot drops a heavy package which falls to the ground. Where, appro
igor_vitrenko [27]

Answer:

128 m

Explanation:

From the question given above, the following data were obtained:

Horizontal velocity (u) = 40 m/s

Height (h) = 50 m

Acceleration due to gravity (g) = 9.8 m/s²

Horizontal distance (s) =?

Next, we shall determine the time taken for the package to get to the ground.

This can be obtained as follow:

Height (h) = 50 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

50 = ½ × 9.8 × t²

50 = 4.9 × t²

Divide both side by 4.9

t² = 50 / 4.9

t² = 10.2

Take the square root of both side

t = √10.2

t = 3.2 s

Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:

Horizontal velocity (u) = 40 m/s

Time (t) = 3.2 s

Horizontal distance (s) =?

s = ut

s = 40 × 3.2

s = 128 m

Therefore, the package will land at 128 m relative to the plane

6 0
3 years ago
help me pass the test please there is a couple of questions in my profile to answer i am leaving this one for you to help ​
kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

6 0
2 years ago
A coin mass 0.005 kg is dropped from a height of 3 m. How much mechanical energy does it have right before it hits the ground ?
lesya692 [45]
Mechanical energy equals the sum of potential and kinetic energy. During the process, all PE converts into KE, assuming air resistance is neglected. So, the mechanical energy does not change and is equal to the initial potential energy.
ME
=mgh
=0.005 x 9.81 x 3
=0.147J
6 0
3 years ago
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