Question

A tank whose bottom is a mirror is filled with water to a depth of 20.1 cm . A small fish floats motionless 6.20 cm under the surface of the water. A) What is the apparent depth of the fish when viewed at normal incidence to the water?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.
B) What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.

Answer 1

Answer:

A) 4.66 cm

B) 25.56 cm

Explanation:

A) real depth of fish = 6.2 cm

apparent depth =d

Now $\frac{6.2}{d}$= 1.33

$d = \frac{6.2}{1.33}$

d = 4.66 cm

B) Image of fish will be formed 13.9 cm behind the mirror so its position from

surface of water will be

20.1 + 13.9 = 34 cm . This will be real depth of image

If D be its apparent depth then

\frac{34}{D}=1.33

D =\frac{34}{1.33}

D = 25.56 cm