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2 years ago

SOMEONE PLEASE PLEASE HELP PLEASE HELP

Mathematics

1 answer:

mr Goodwill [35]2 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ = $\frac{1}{a^{-m} }$ , then

2 ÷ $10^{4}$ = 2 ÷ $\frac{1}{10^{-4} }$

To divide leave first, change ÷ to × , turn second upside down

= 2 × $10^{-4}$

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Whitepunk [10]

It's either A or B I'm not sure which but it is one of them thats correct sorry if this doesn't help that much

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3 years ago

A wheel of radius 10 inches is rotating 20°/sec. What is the linear speed in in/sec and the angular speed in RPM? (Round your an

Assoli18 [71]

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Answer:

a) 3.491 in/s

b) 3.333 RPM

c) 0.349 rad/s

Step-by-step explanation:

We know the arc length for a given radius and angle is ...

s = rθ

so the linear speed along the arc is ...

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2 years ago

When Jennifer purchases her house, she pays a 3% realtor commission for the $1800,000 loan amount. How much commission did Jenni

ankoles [38]

Answer:

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Step-by-step explanation:

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1 year ago

Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)

vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

$y-y_0 = m(x-x_0)$ or equivalently

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Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$

The slope of the tangent line is given by the derivative of the function evaluated at $x_0$ . Using the properties of derivatives, we get

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Replacing the values in our previous findings we get that the y intercept is

$(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}$

The x intercept is

$\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0$

The triangle in consideration has height $\frac{2}{x_0}$ and base $2x_0$ . So the area is

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So regardless of the point we take on the graph, the area of the triangle is always 2.

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Ne4ueva [31]

Answer:

Step-by-step explanation:

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