Answer:
24 Domain: s>=2 or s<=-2
25. 3x^2 +14x +10
26. x^2 -2x+5
Step-by-step explanation:
24. Domain is the input or s values
square roots must be greater than or equal to zero
s^2-4 >=0
Add 4 to each side
s^2 >=4
Take the square root
s>=2 or s<=-2
25. f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = 3u^2 +2u-6
g(x) = x+2
f(g(x) = 3(x+2)^2 +2(x+2) -6
Foil the squared term
= 3(x^2 +4x+4) +2x+4-6
Distribute
= 3x^2 +12x+12 +2x+4-6
Combine like terms
=3x^2 +14x +10
26 f(g(x)) stick g(x) into f(u) every place you see a u
f(u) = u^2+4
g(x) = x-1
f(g(x) = (x-1)^2 +4
Foil the squared term
= (x^2 -2x+1) +4
= x^2 -2x+5
Answer- seriously? Not sure if I should answer this. But it’s 4 (duh)
Step-by-step explanation:
You already know. You have two, add two, 4.
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
Answer:
7 and 5
Step-by-step explanation:
7+5=12 and 7-5=2
