Answer:
4 7/8 or 4.875
Step-by-step explanation:
1 1/4 + 3 5/8 = 4 7/8 or 4.875
PLEASE MARK ME AS BRAINLIEST UWU
Answer:
2y -6
Step-by-step explanation:
5y - 3(y+ 2)
Distribute
5y -3y -6
Combine like terms
2y -6
Hello:
<span>Use De Moivre’s Theorem :
</span>(3(cos27 +isin27)^5 = 3^5( cos(27 × 5) +isin(27 × 5))
= 3^5 ( cos(135)+i sin(135))
= 3^5(-√2/2+i √2/2)
because : cos(135) = -√2/2 and sin(135) = √2/2
(3(cos27 +isin27)^5 = (- 3^5√2/2)+ i ( 3^5√2/2) ...(form : a+ib when
a= (- 3^5√2/2) and b = ( 3^5√2/2)
<span>1) if 2 times the wind speed is increased by 2, the wind speed is still less
than 46 km/h.
=> 2x + 2 < 46
2) Twice the wind speed minus 27 is greater than 11 km/h.
=> 2x - 27 > 11
Part A: Create a compound inequality to represent the wind speed range.
(3 points)
from 2x + 2 < 46
=> 2x < 44
=> x < 22
from 2x - 27 > 11
=> 2x > 11 + 27
=> 2x > 38
=> x > 19
The set of inequalities is
2x + 2 <46
2x - 27 > 11
The solution is x < 22 and x > 19, which is:
19 < x < 22 <----- answer
Part B: Can the wind speed in this town be 20 km/h? Justify
your answer by solving the inequalities in Part A. (3 points)
Yes, the wind speed can be 20 km/h, because the solution of the inequality is the range (19,22).
Part C:
The average wind speed in another town is 23 km/h, but the actual wind
speed is within 4 km/h of the average. Write and solve an inequality to
find the range of wind speed in this town.
x ≥ 23 - 4 => x ≥ 19
x ≤ 23 + 4=> x ≤ 27
=> 19 ≤ x ≤ 27
=> [19,27]
</span>
The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.
Step-by-step explanation:
The given is,
Park and movie theater are 3.4 inches apart
Map has a scale of 0.25 inch = 5 miles
Step:1
Formula to calculate the number of scales for distance between park and theater,
= 13.6
number of scales for distance between park and theater = 13.6
Step:2
Formula to convert distance inches to miles
× 
= 13.6 × 5
= 68
Actual distance between park and theater = 68 miles
Result:
The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.
