Answer:
⅜ or ⅗
Step-by-step explanation:
I say ⅜ because of how many variables you can take into account 3 different colors, and a 2 sided coin, lastly 3 different numbers. So in total that is 8 possible variables and the 3 being blue, heads, and landing on 1.
Now I say ⅗ because of this perspective on the variables. You have the 3 colors, and your two sided coin but thing here is that the 1 is basically another color so the question is technically asking for the probability of spinning blue, landing on heads and landing on red in a sense.
Go with your gut though between those 2
If there are that many things missing then go left to right; 5+1 then multiply the sum by ten
5+1=6
6x10=60
I hope I was helpful
<span>$8 each month
</span><span>How many months will it take him to save at least $60?
60 </span>÷ 8 = 7.5
It will take Phillip 7.5 months to save up at least $60!
Answer:
See explanation below
Step-by-step explanation:
Let's use Q10 as an example and you will work on Q11-12 as they are the same.
I believe the middle column (5x-4) wants you to substitute the given x, so:
Q10.1: 5(-2)-4
Q10.2: 5(4)-4
Q10.3: 5(0)-4
Q10.4: 5(1)-4
The right most column (f(x)) should be asking you the answers from your middle column, so:
Q10.1: -14
Q10.2: 16
Q10.3: -4
Q10.4: 1
As for the domain and range, let's define these two names in case you haven't learnt them:
Domain: What reasonable x values can be inputted into the function.
Range: What reasonable results will be shown after calculating.
In these case, you can input any real numbers into x as you like into the function, the results will always be other real numbers.
Hence, for Q10-12, D and R should be "All real numbers"
Just some extra info, Let the function f(x) be
. Since the denominator cannot be 0 in a fraction, we say that the domain of x is "All real numbers except -1" as
and
is undefined.
Answer:
<u>x</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>8</u><u>°</u><u> </u>and <u>y</u><u> </u><u>is</u><u> </u><u>1</u><u>4</u><u>4</u><u>°</u>
Step-by-step explanation:
for x:

for y:
