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mr Goodwill [35]
2 years ago
6

Elise says, "If you subtract 14 from my number and multiply the difference by - 3, the result is - 63."

Mathematics
2 answers:
Ksivusya [100]2 years ago
6 0
Answer:
35

Explanation:
Let x be equal to Elise’s number.
We can set up our equation like this:

(x-14)(-3)=-63
Expand the parentheses
-3x+42=-63
Subtract both sides by 42
-3x+42-42=-63-42
-3x=-105
Divide both sides by -3
-3x/-3=-105/-3
x=35

I hope this helps!
igor_vitrenko [27]2 years ago
5 0

Answer:

35

Step-by-step explanation:

-3(x-14)=-63

distribute

-3x+42=-63

-3x=-105

x=35

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Step-by-step explanation:

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Find both x and y. Leave answers in simplified radical from. (Step by step)
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60 +30+ x =180

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Apply each of the four counting/sampling methods (with replacement and with ordering, without replacement and with ordering, wit
dusya [7]

Answer:

Step-by-step explanation:

I will illustrate this solution with a unique birthday party situation between Jane (the celebrant) and her 10 friends.

In the said party , we will assume that Jane only has 5 chocolates to share among her friends

i. Assuming that the 5 chocolates are of the same type, if she doesn't want to give any friend more than one piece of chocolate, the situation here is said to be WITHOUT REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

(\left {n} \atop {k}} \right. )=(\left {10} \atop {5}} \right. )=252

ii. Assuming that the 5 pieces of chocolate are of the same type and she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

(\left {n+k-1} \atop {k}} \right. )=(\left {14} \atop {5}} \right. )=2002

iii. Assuming that the 5 pieces of chocolate are of different types and she isn't willing to give any friend more than one piece of chocolate, the situation is said to be WITHOUT REPLACEMENT & ORDERED

n = 10 & k = 5

Total number of possible combinations becomes,

P\left {n} \atop {k}} \right=P\left {10} \atop {5}} \right. =30240

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n = 10 AND k = 5

Total number of combinations becomes

n^k=10^5=100,000

Sampling with replacement means that one friend can be sampled more than once i.e: A friend receives a piece of chocolate more than once

The order dictates how the sampling is applied.

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