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algol [13]
3 years ago
6

Does the data in the table represent a direct variation or an inverse variation? Write an equation to model the data in the tabl

e. x 2 4 8 12 y 4 2 1 2/3
Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

The equation for the direct variation is y= kx (where k is contant of variation.)

This equation represent that if x will increase then y will also increase because it's k times x.

Where the equation for indirect variation is y=\frac{1}{k} x

By this equation if x will increase then y will decrease and vice versa.

The given data is :

x: 2 4 8 12

y: 4 2 1 2/3

Notice as x is increasing then y is decreasing. Like x has increased from 2 to 4 then y is decresing from 4 to 2 and so on.

So, the given data represent an indirect variation.

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Answer:

319 is the term

Step-by-step explanation:

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Need Help!!! ASAP
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Answer:

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}

Step-by-step explanation:

The given probabilities are:

P(red)=\frac{2}{7}

P(blue)=\frac{3}{14}

Their sum is P(red)+P(blue)=\frac{2}{7}+\frac{3}{14}

The probabilities that will complete the model should add up to \frac{1}{2} so that the sum of all probabilities is 1.

P(green)+P(yellow)=\frac{2}{7}+\frac{2}{7}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}=\frac{1}{2}

P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}

P(green)+P(yellow)=\frac{5}{21}+\frac{11}{21}\ne\frac{1}{2}

P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}=\frac{1}{2}

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3 years ago
Suppose that 20% of the residents in a certain state support an increase in the property tax. An opinion poll will randomly samp
aleksklad [387]

Answer:

95.44% probability the resulting sample proportion is within .04 of the true proportion.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sampling distribution of the sample proportion in sample of size n, the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.2, n = 400

So

\mu = 0.2, s = \sqrt{\frac{0.2*0.8}{400}} = 0.02

How likely is the resulting sample proportion to be within .04 of the true proportion (i.e., between .16 and .24)?

This is the pvalue of Z when X = 0.24 subtracted by the pvalue of Z when X = 0.16.

X = 0.24

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

Z = \frac{0.24 - 0.2}{0.02}

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Z = \frac{X - \mu}{s}

Z = \frac{0.16 - 0.2}{0.02}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

95.44% probability the resulting sample proportion is within .04 of the true proportion.

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