1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlexFokin [52]
3 years ago
11

Actually thats wrong bc my teacher did it with us but i really dont know the answer

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

???

Step-by-step explanation:

Anon25 [30]3 years ago
3 0
Darn
do u have the question lololol
You might be interested in
The function f(x) = x2 is transformed to f(x) = −1.4x2. Which statement describes the effect(s) of the transformation on the gra
Romashka-Z-Leto [24]

Answer:

C) The parabola is narrower and reflected across the x-axis.

Step-by-step explanation:

The original parabola has equation:

f(x) =  {x}^{2}

The transformed parabola has equation

f(x) =  - 1.4 {x}^{2}

How wide the graph is can be determined by the absolute value of the coefficient.

The smaller the absolute value of the coefficient, the wider the graph.

Since

|1|  \:  <  \:  | - 1.4|

The original graph is wider than the transformed graph.

Also the negative factor tells us there is a reflection in the x-axis.

3 0
3 years ago
Question 1
Arada [10]
The answer is n+7 and 7+n
5 0
3 years ago
Write each pair of quantities as a unit rate.
Ronch [10]
A) 75heartbeats per min
B) $9.35 per ticket
C) 2.25 per golf ball
D) $9.75 per hour
3 0
2 years ago
The position of an object at time t is given by s(t) = -9 - 3t. Find the instantaneous velocity at t = 8 by finding the derivati
pogonyaev
Given the function s(t) = -9 -3t, differentiating the function gives the instantaneous velocity. s’(t) = -3 This means that the velocity is not a function of time and is therefore constant. The velocity at t = 8 ( or any time for that matter) is -3 units/time.
4 0
2 years ago
The base of a right triangle is increasing at a rate of 2 meters per hour and the height is decreasing at a rate of 3 meters per
STatiana [176]

Answer:

dL/dt  = - 2,019 m/h

Step-by-step explanation:

L²  =  x²  +  y²   (1)    Where  x, and  y are the legs of the right triangle and L the hypotenuse

If the base of the triangle, let´s call x is increasing at the rate of 2 m/h

then  dx/dt =  2 m/h. And the height is decreasing at the rate of 3 m/h or dy/dt = - 3 m/h

If we take differentials on both sides of the equation (1)

2*L*dL/dt = 2*x*dx/dt  + 2*y*dy/dt

L*dL/dt  = x*dx/dt + y*dy/dt         (2)

When  the base is 9  and the height is 22 according to equation (1) the hypotenuse is:

L = √ (9)² + (22)²       ⇒    L = √565       ⇒  L  = 23,77

Therefore we got all the information to get dL/dt .

L*dL/dt  = x*dx/dt + y*dy/dt

23,77 * dL/dt  = 9*2 + 22* ( - 3)

dL/dt  =  ( 18 - 66 ) / 23,77

dL/dt  = - 2,019 m/h

6 0
3 years ago
Other questions:
  • Write the equation of the line, in point slope form identify x,y as the point (-2,2)
    12·1 answer
  • Answer this 4(−12)(−3)
    6·1 answer
  • Colton scored a 70 on his first history test of the term and a 91 on the second history test. By what percent did Colton's score
    10·1 answer
  • A guide wire for a palm tree makes a 32°angle with the ground and is staked 6 feet from the base of the tree. What is the length
    13·2 answers
  • Whats equivalent to 4/16
    10·2 answers
  • An edge of a flow network is called critical if decreasing the capacity of this edge results in a decrease in the maximum flow.
    12·1 answer
  • If f(x)=x^3+3x+5 what is f(a+h)
    7·1 answer
  • The following stem-and-leaf plot represents the times in minutes required for 26 co-workers to commute to work. Use the data pro
    11·1 answer
  • 2. A landscaper drew a scale drawing of a rectangular yard using the scale, , before beginning to work on the yard.(a) The lands
    15·1 answer
  • For each function, find f(-1), f(1), and f(3)<br> f(x)=3x-4
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!