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AlexFokin [52]
4 years ago
11

Actually thats wrong bc my teacher did it with us but i really dont know the answer

Mathematics
2 answers:
Dvinal [7]4 years ago
8 0

Answer:

???

Step-by-step explanation:

Anon25 [30]4 years ago
3 0
Darn
do u have the question lololol
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Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. x2+3/2x
denis23 [38]

Answer:

The added term needed for that expression to be a square is 9/16.

Step-by-step explanation:

We're provided with two terms, and asked to add an additional term to make this a perfect square.  For this to work, the term needs to be a scalar value that is the square of half the coefficient of the second term.

That coefficient is 3/2, so half of that is 3/4, and its square is 9/16.

If we tack that on the end then, we get:

x^2 + \frac{3x}{2} + \frac{9}{16}\\=(x + \frac{3}{4})^2

To confirm the answer, let's expand it and see if we get the original expression:

(x + \frac{3}{4})^2\\= (x + \frac{3}{4})(x + \frac{3}{4})\\= x^1 + \frac{3x}{4} + \frac{3x}{4} + \frac{9}{16}\\= x^2 + \frac{6x}{4} + \frac{9}{16}\\=x^2 + \frac{3x}{2} + \frac{9}{16}

So 9/16ths is the scalar that needs to be added on the end.

4 0
3 years ago
1) Jack is rolling a number cube. What is the probability that he will roll a 4? Write your answer as a fraction, decimal and eq
Alja [10]

Answer:

Look below!

Step-by-step explanation:

1.

1A (fraction): 1/6

1B (decimal): 0.16 (6 continues)

1C (percent): 16.66 (6 continues)

2.

5+15+7+8+10+15=60

10/60 time she got 5

1/6 chance she gets a 5 again

2A (fraction): 1/6

2B (decimal): 0.16 (6 continues)

2C (percent): 16.66 (6 continues)

3.

Yellow: 3/10 chance

Red: 1/5 chance

Blue: 2/5 chance

Pink: 0/20 chance

You're welcome in advance.

8 0
4 years ago
A red blinking light blinks every 18 seconds, while a yellow blinking light blinks every 12 seconds. If both lights start at the
Mice21 [21]
Option C, 36, because it is the LCM (Least common multiple)
4 0
4 years ago
Read 2 more answers
Sin(5x)sin(3x)
LekaFEV [45]

\bf \textit{Product to Sum Identities} \\\\ sin(\alpha)sin(\beta)=\cfrac{1}{2}[cos(\alpha-\beta)\quad -\quad cos(\alpha+\beta)]\qquad \leftarrow \textit{we'll use this one} \\\\\\ cos(\alpha)cos(\beta)=\cfrac{1}{2}[cos(\alpha-\beta)\quad +\quad cos(\alpha+\beta)] \\\\\\ sin(\alpha)cos(\beta)=\cfrac{1}{2}[sin(\alpha+\beta)\quad +\quad sin(\alpha-\beta)]

\bf cos(\alpha)sin(\beta)=\cfrac{1}{2}[sin(\alpha+\beta)\quad -\quad sin(\alpha-\beta)] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(5x)sin(3x)\implies \cfrac{cos(5x-3x)-cos(5x+3x)}{2}\implies \cfrac{cos(2x)-cos(8x)}{2}

6 0
3 years ago
Read 2 more answers
Can somebody please help me and give me the answer to example 2
Salsk061 [2.6K]

Answer:

there is no question for example 2

Step-by-step explanation:

5 0
3 years ago
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