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NISA [10]
2 years ago
12

Which equation has a slope of -2 and passes through the point (1,-6)?

Mathematics
1 answer:
Naily [24]2 years ago
7 0

Answer:

y=-2x-4

Step-by-step explanation:

Given that,

Slope, m = -2

It passes through the point (1,-6).

We need to find the equation of line that passes throgh the given point. It can be calculated as:

y-y_1=m(x-x_1)

Put y₁ = -6, x₁ = 1 and m = -2

y-(-6)=(-2)(x-1)\\\\y+6=-2x+2\\\\y+2x+6-2=0\\\\y=-2x-4

Hence, the equation of line is y=-2x-4.

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Suppose that F(x) = x2 and G(X) = 2/3 x^2. Which statement best compares the graph of G(x) with the graph of F(x)?
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<h2>Answer:The graph of G(x) is the graph of F(x) compressed vertically.</h2>

Step-by-step explanation:

Given that F(x)=x^{2} and G(x)=\frac{2}{3}x^{2}

F(x) is always positive because x^{2} is always positive.

G(x) is always positive because \frac{2}{3}x^{2} is always positive.

So,both are always positive.

So,there is no flipping over x-axis.

In F(x),the height of a point at x_{0} is x_{0}^{2}

In G(x),the height of a point at x_{0} is \frac{2}{3}x_{0}^{2}

So,height of any point has less height in G(x) than F(x)

So,the graph of G(x) is the graph of F(x) compressed vertically.

3 0
3 years ago
Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 8% each week. The following function represents t
dybincka [34]

The function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily

<h3>How to rewrite the function?</h3>

The function is given as:

f(x) = 86(1.08)^x

There are 7 days in a week.

This means that:

1 day = 1/7 week

So, x days is

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r = 1.01 - 1

Evaluate

r = 0.01

Express as percentage

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Hence, the function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily

Read more about exponential functions at:

brainly.com/question/11487261

#SPJ1

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