Which of the following galaxy types is usually made of mostly older stars

Many kinds of roses have sharp thorns covering the stem of the plant. Thorns most likely perform which function?

mamaluj [8]

C) Help with plant defense.

Many species are known to eat many plants, including flowers. To avoid being eaten, thorns in a rose bush help defend itself.

3 0

3 years ago

Simone is creating a model to track the movement of carbon atoms in an ecosystem. Which statement best explains the role of plan

Mademuasel [1]

Although I cannot see the model for Simone's experiment, I can offer the insight that the most likely role of plants in the model is that they consume the carbon atoms and produce oxygen.

<h3>How do plants affect the carbon in the atmosphere?</h3>

Plants are known to have a<u> great effect</u> on the carbon levels of the atmosphere.
The correlation is that the more plants are present, the less carbon is free in the air.
The reason for this is that plants use carbon dioxide as a substrate to manage the process of photosynthesis.
As a by-product, after consuming carbon dioxide and completing photosynthesis, plants release oxygen into the atmosphere.

Therefore, we can confirm that the most likely role of plants in the model created by Simone, is that they will consume carbon atoms in the form of carbon dioxide in order to sustain photosynthesis, which releases oxygen.

To learn more about photosynthesis visit:

brainly.com/question/1388366?referrer=searchResults

6 0

2 years ago

In order for an ecosystem to be healthy is does not need to have different kinds of plants and animals.

soldier1979 [14.2K]

Answer:

false

Explanation:

biodiversity is crucial to a healthy ecosystem

7 0

2 years ago

4. A grouping based on the ability of members to

agasfer [191]

Answer: it is species!

Explanation: species is a GROUP of individual organisims that inter breed with others!

5 0

3 years ago

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny pl

nalin [4]

Here is the complete question

The seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white seed color in bush beans.

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of:

A) 4 green and 2 white seeds?

B) all white seeds?

C) at least 5 white seeds?

Answer:

A) 0.3

B) 0.0002

C) 0.001

Explanation:

Let the allele for Green plant be = P

Let the allele for white plant be = p

Let the heterozygous plant be Pp, if self fertilization occurs we have:

P p

P PP Pp

p Pp pp

From the punnet square above, we have the following cross;

PP, Pp, Pp, pp

Since P is dominant to p; we have a phenotypic ratio of 3:1 between the dominant phenotype ( PP, Pp, Pp ) and recessive phenotype ( pp )

NOW, the probability for the green plant(i.e PP or Pp) will be: $Pr(G)=\frac{3}{4}$

the probability for the white plant (pp) will be: $Pr (W)= \frac{1}{4}$

A)

what is the probability that 6 seeds in a single pod of the progeny plant will consist of 4 green and 2 white seeds?

$Pr(4G2W)$ = $(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

The probability includes the use of permutation:

$Permutation(P)=\frac{6!}{(4!*2!)} * (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= $15*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= 0.2966

≅ 0.3

B)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of all white seeds?

Since probability for white seed = $\frac{1}{4}$

The probability that 6 seeds will consist of all white seeds will be = $(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

≅ 0.0002

C)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of at least 5 white seeds?

For at least 5 white seeds, the probability will consist of 5 white seeds and 6 white seeds.

For 5 white seeds; we have:

5 White and 1 Green Since there are 6 permutations.

The probability For 5 white seeds will therefore be :

$Pr(5 seeds)=(\frac{1}{4})^5*(\frac{3}{4})^1 *6$

= 7.32 × 10⁻⁴

= 0.000732

For 6 white seeds; we have:

Only one permutation for 6 whites since there will no be any presence of any green seed.

$Pr(6seeds)=(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

∴

The total probability for at least 5 white seeds = 0.000732 + 0.000244

= 9.76 × 10⁻⁴

= 0.000976

≅ 0.001

3 0

4 years ago